Question

#!/usr/bin/python3.5

import os, sys

from time import strftime
from os.path import join

path = '/home/william/.btrfs-snapshots/'
age = 24
todaytuple = (int(strftime("%y")),int(strftime("%m"))int(strftime("%d")))



def get_date_tuple(filename):
    numberstr = ('1', '2', '3', '4', '5', '6', '7', '8', '9', '0')
    filename = ''
    datelist = []
    global datepart
    datepart = ''


    for i in filename:
        for n in numberstr:
            if i == n:
                datepart += i
                if len(datepart) == 2:
                    y = int(datepart)
                    datelist.append(y)
                    datepart = ''
            else:
                pass
    snapshotbirthtuple = tuple(datelist)
    return snapshotbirthtuple


for fname in os.listdir(path):
    snapshotbirthtupleinscope = get_date_tuple(fname)
    print(snapshotbirthtupleinscope)
    if snapshotbirthtupleinscope[0] <= todaytuple[0]:

print(snapshotbirthtupleinscope)打印()只是空括号，我期待一对数字的元组。我很确定该函数提供了正确的输出，但我想我可能没有正确地从函数中传递返回变量。

() #the tuple returning nothing
Traceback (most recent call last):
  File "./snapshotfinal.py", line 38, in <module>
    if snapshotbirthtupleinscope[0] <= todaytuple[0]:
IndexError: tuple index out of range

为什么是snapshotbirthtupleinscope！= snapshotbirthtuple？

Answer 1

看起来你可以使用一些工作。首先根据您的变量名称，您需要为filename分配一些内容，例如：

filename = r"C:\MyFile.txt"

完成后，您将需要打开文件并解析其内容：

 with open( filename, "r") as fp:
        data = fp.read()
        # Process Data In File where datelist is set
 # end with automatically closes file for you

 snapshotbirthtuple = tuple(datelist)
 return snapshotbirthtuple

原始代码没有回答的原因是因为行：

for i in filename:

filename是一个空字符串，没有任何内容可以迭代，因此永远不会为i分配任何值。因此，您的循环完全被跳过，因此日期列表永远不会被分配

函数返回没有任何内容的元组

1 个答案: