Question

我在Ubuntu 14.04上输入此代码

#include<stdio.h>
int main() {

  int i, j, n;
  scanf("%",&n);
  for (i=0;i<=n;i++){
    for (j=0;j<=i;j++){
        printf("*");
    }
    printf("\n");
  }
  return 0;
}

但它打印的星星太多而且一直持续到关闭它为止。

Answer 1

应该是：

function getToken() {
    if (customerToken) {
        return Promise.resolve(customerToken);
    } else {
        // Asynchronous call to Stripe to get the data that will be stored as customerToken
        return Stripe.customers.create({
            source: stripeToken,
            email: customerEmail,
        }).then(function(customer){
            // Note: this request() is sent asynchronously and
            // this promise does not wait for it's response
            // You could make it wait by returning a promise here
            // store customerToken on my end
            request({
                url:'[anAPI]',
                method: 'POST',
                json: {customerToken: customer}
            });
            return customer;
        });    
    }
}

getToken().then(function(token) {
    // use the token here
});

您忘记告诉scanf您使用％d参数

读取整数

Answer 2

中有错误

的scanf（＆＃34;％＆＃34;，＆安培; N）;

它将是：

的scanf（＆＃34;％d＆＃34;，＆安培; N）;

告诉编译器n的值是整数类型。

打印太多星星

2 个答案: