我在弹簧启动应用程序中配置了过滤器的代码。当我提出请求时,我的第二个过滤器是B,不会调用。
import org.springframework.security.config.annotation.web.builders.HttpSecurity;
import org.springframework.security.config.annotation.web.builders.WebSecurity;
import org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter;
import org.springframework.security.config.annotation.web.servlet.configuration.EnableWebMvcSecurity;
@Configuration
@EnableWebMvcSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {
@Override
public void configure(WebSecurity webSecurity) throws Exception {
webSecurity.ignoring().antMatchers(HttpMethod.GET, "/health");
}
@Override
protected void configure(HttpSecurity http) throws Exception {
http.sessionManagement().sessionCreationPolicy(SessionCreationPolicy.STATELESS);
http.addFilterBefore(new A(), BasicAuthenticationFilter.class);
http.addFilterAfter(new B(), new A().getClass());
}
}
import org.springframework.web.filter.GenericFilterBean;
public class A extends GenericFilterBean {
@Override
public void doFilter(ServletRequest arg0, ServletResponse arg1, FilterChain arg2)
throws IOException, ServletException {
System.out.println("filter A");
}
}
import org.springframework.web.filter.GenericFilterBean;
public class B extends GenericFilterBean {
@Override
public void doFilter(ServletRequest arg0, ServletResponse arg1, FilterChain arg2)
throws IOException, ServletException {
System.out.println("filter B");
}
}
编辑:
public class A extends GenericFilterBean {
@Override
public void doFilter(ServletRequest arg0, ServletResponse arg1, FilterChain arg2) throws IOException, ServletException {
System.out.println("filter A Before");
arg2.doFilter(arg0,arg1);
System.out.println("filter A After");
}
}
答案 0 :(得分:4)
您的配置正确无误。但是,如M. Deinum所述,您需要将请求从Filter A
传递给Filter B
。只是印刷不会工作。在您的代码中,它应该是arg2.doFilter()
中的Filter A
。
来自docs它说,
此方法的典型实现将遵循以下模式: