我有这个代码,效果很好
$i = 0; // counter
$url = "http://www.banki.ru/xml/news.rss"; // example url to parse
$rss = simplexml_load_file($url); // XML parser
print '<h2><img style="vertical-align: middle;" src="'.$rss->channel->image->url.'" /> '.$rss->channel->title.'</h2>'; // channel title + img with src
foreach($rss->channel->item as $item) {
if ($i < 1) { // parse only 1 item
print '<a href="'.$item->link.'">'.$item->title.'</a><br />';
}
$i++;
}
但我想只显示此Feed中的第二项。我怎么能这样做?
答案 0 :(得分:3)
更改此
if ($i < 1) { // parse only 1 item
print '<a href="'.$item->link.'">'.$item->title.'</a><br />';
}
到
if ($i == 1) { // parse only 1 item
print '<a href="'.$item->link.'">'.$item->title.'</a><br />';
}
答案 1 :(得分:0)
尝试:
$i = 0; // counter
$url = "http://www.banki.ru/xml/news.rss"; // example url to parse
$rss = simplexml_load_file($url); // XML parser
print '<h2><img style="vertical-align: middle;" src="'.$rss->channel->image->url.'" /> '.$rss->channel->title.'</h2>'; // channel title + img with src
print '<a href="'.$rss->channel->item[1]->link.'">'.$rss->channel->item[1]->title.'</a><br />';
答案 2 :(得分:0)
只需更改if条件就可以获得第二个会话
<?php
$i = 0; // counter
$url = "http://www.banki.ru/xml/news.rss"; // example url to parse
$rss = simplexml_load_file($url); // XML parser
print '<h2><img style="vertical-align: middle;" src="'.$rss->channel->image->url.'" /> '.$rss->channel->title.'</h2>'; // channel title + img with src
foreach($rss->channel->item as $item) {
if ($i > 1) { // parse only 1 item
print '<a href="'.$item->link.'">'.$item->title.'</a><br />';
}
$i++;
}
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