如何让它检测输入？在python中

Question

我试图建立一个这样的商店系统：

def Command():
    Command = input("Press \"C\" to continue and earn $1 or \"S\" to go to the Shop! -->")

def Display_Shop():
    print ("Buy stuff at the Shop like:")
    print ("")
    print ("Double Money - Gives you $2 instead of $1")
    item = input("Which item do you want?")
    if item == ("Double Money"):
    doubleMoney = True
    print("Added (Double Money)")
Work1()


def Work1():
Chop = input('Type \"C\" to earn $1 -->')
global Win
if Chop == ('C') and Win == False:
    global gold
    global Command
    time.sleep(1)
    print ('$1 earned')
    if doubleMoney == True:
        gold = gold+2
    if doubleMoney == False:
        gold = gold+1
    displayMoney()
    Chop = 0
    Command()
    if gold == 100:
        Win = True
Work1()

我的问题是，每次我运行它，我都会看到问题：

 "Press \"C\" to continue and earn $1 or \"S\" to go to the Shop! -->"

我键入“S”并注册为“C”并运行Work1（）。我该如何解决这个问题，以便注册为“S”？请尽快回复。谢谢！