我有一个测试的rest API,我必须比较两个json响应。您可以在下面找到该文件的结构。要比较的两个文件应包含相同的元素,但顺序可能不同。不幸的是,名称,类型(简单,数组)和键数(root,nodeXYZ)也是未知的。
{"root": [{
"node1": "value1",
"node2": "value1",
"node3": [
{
"node311": "value311",
"node312": "value312"
},
{
"node321": "value321",
"node322": "value322"
}
],
"node4": [
{
"node411": "value411",
"node412": "value413",
"node413": [ {
"node4131": "value4131",
"node4132": "value4131"
}],
"node414": []
}
{
"node421": "value421",
"node422": "value422",
"node423": [ {
"node4231": "value4231",
"node4232": "value4231"
}],
"node424": []
}]
"node5": [
{"node51": "value51"},
{"node52": "value52"},
]
}]}
我在中找到了一些有用的信息 Groovy - compare two JSON objects (same structure) and return ArrayList containing differences Getting node from Json Response Groovy : how do i search json with key's value and find its children in groovy 但我无法将它与解决方案结合起来。 我认为解决方案可能如下所示:
take root
get root children names
check if child has children and get their names
do it to the lowest leve child
所有名称都比较应该很容易(我猜) 不幸的是,我没有设法在root下获取密钥
答案 0 :(得分:6)
只需比较潦草的地图:
def map1 = new JsonSlurper().parseText(document1)
def map2 = new JsonSlurper().parseText(document2)
assert map1 == map2
答案 1 :(得分:2)
尝试JSONassert库:https://github.com/skyscreamer/JSONassert。然后你可以使用:
main
你将得到格式良好的增量,如:
JSONAssert.assertEquals(expectedJson, actualJson, JSONCompareMode.STRICT)