Question

我有一个如此定义的类：

[DataContract]
public class Response2
{
    [DataMember(Name = "done")]
    public bool done;
    [DataMember(Name = "records")]
    public List<Response3> r3entry;
}

[DataContract]
public class Response3
{
    [DataMember(Name = "Id")]
    public string strId { get; set; }
    [DataMember(Name = "Name")]
    public string strName { get; set; }
}

现在，我想要发生的是从另一个类中获取值并填充......这样的事情：

string propertyRequest2 = CreatePropertyRequest2();
Response2 propResponse2 = MakeRequest2(propertyRequest2, sfToken);

List<Response> listAllData = new List<Response>();

foreach (var responseEntry in propResponse2.r3entry)
{
    listAllData.Add(new Response() { strId = responseEntry.strId, strName = responseEntry.strName } );

    // NOTE .strId IS ALWAYS UNIQUE IN BOTH CLASSES
    // - I know this is NOT the right syntax... will fix later.
    Where listAllData.strId = responseEntry.strId
    {
        listAllData.property = propertyResponse2(.strId=responseEntry.strId).property
    }
}

我确信（至少）代码的最后一点对大多数阅读此内容的人来说都是痛苦的，但我会解决这个问题并不是那么可怕。我只是不知道解释它是否清楚。万一我错了，这里的重点更像是：

// WE HAVE A LIST OF CLASSES WITH PROPERTIES
// ASSUME PROPERTIES ARE ID, ITEM, NAME
LIST1 = { ("1", "A", "APPLE"), ("2", "B", "BANANA"), ("3", "C", "COCONUT")}

// NOW WE HAVE ANOTHER LIST THAT HAS THE SAME ID BUT DIFF DATA
// ASSUME PROPERTIES ARE ID, COLOR
LIST2 = { ("1", "RED"), ("2", "YELLOW"), ("3", "BROWN) }

// AND THEN I WANT TO CREATE A NEW LIST WITH BOTH SETS OF DATA COMBINED
// ASSUME PROPERTIES ARE ID, ITEM, NAME, COLOR
LIST3 = { ("1", "A", "APPLE", "RED"), ("2", "B", "BANANA"), ("3", "C", "COCONUT", "BROWN") }

关于如何做到这一点的任何想法？

Answer 1

带投影的内部联接：

var list = from l1 in LIST1
    join l2 in LIST2 on l1.ID equals l2.ID
    select new {
        l1.ID,
        l1.Item,
        l1.Name,
        l2.Color
    }
    .ToList()

Answer 2

如果不确切知道你的目标是什么，Zip函数会作用于两个列表并返回这两个列表的产品。你可以在这里阅读更多内容：

Zip on MSDN

但实际上，如果您有两个事项列表，请说：

alert

所以在你的情况下，它可能是这样的：

int[] numbers = { 1, 2, 3, 4 };
string[] words = { "one", "two", "three" };
// The following example concatenates corresponding elements of the
// two input sequences.
var numbersAndWords = numbers.Zip(words, (first, second) => first + " " + second);

这会将response2的第一个元素与response3的第一个元素配对，依此类推。我们在这里假设它们具有相同的长度，因此您没有未配对的属性。

你必须找到一种方法将它输出到你可能会觉得有用的东西，但你会有一个列表，它们逐个元素地对应。

如何在C＃中设置List <class>的属性

2 个答案: