XPathSelectElement返回null

Question

这是我的XPath：

./trade/financeLeg/paymentDates/paymentDate[1]

这是我的xml文件：

<dataDocument>
   <trade>
        <underlyingSymbol />
        <quantity />
        <avgPrice />
        <notional />
        <effectiveDate />
        <lookBack>0</lookBack>
        <expirationDate />
        <broker>Select</broker>
        <exchange />
        <equityLeg>
          <frequency>Monthly</frequency>
          <paymentDates>
            <paymentDate />
          </paymentDates>
          <currency>USD</currency>
        </equityLeg>
        <financeLeg>
          <resetDates>
            <resetDate />
          </resetDates>
          <interestRate>0.00</interestRate>
          <spread>0</spread>
          <dayCount>ACT/360</dayCount>
          <frequency>Monthly</frequency>
          <paymentDates>
            <paymentDate />
          </paymentDates>
          <currency>USD</currency>
          <interestRateBenchMark>Select</interestRateBenchMark>
          <marginCollateral>0.00</marginCollateral>
        </financeLeg>
        <dividendLeg>
          <paymentDate />
          <currency>USD</currency>
          <dividedRate>0.00</dividedRate>
          <frequency>Monthly</frequency>
        </dividendLeg>
   </trade>
 </dataDocument>

当我在 XPathSelectElement 上使用XPath时，它返回'null'，我意识到这可能是由于标记为空。但是使用Xpath获取元素的最佳方法是什么？

Answer 1

xpath中的

/表示从根开始查找 如果您使用/，您可以尝试/ dataDocument / trade / financeLeg / paymentDates / paymentDate [1]

我相信你想用 //贸易/ financeLeg / paymentDates / PAYMENTDATE [1]

Answer 2

我意识到这是因为我将XML保存为空节点，因为我将其更改为，我能够使xpath工作