SpyOn返回预期的间谍,但得到了功能

时间:2015-10-27 17:34:25

标签: unit-testing service controller karma-runner spyon

我正在测试一个调用服务的控制器(通过goToPage函数),以便使用spyOn重定向。这很简单,但我得到了#34;期待间谍,但得到了功能。"错误。我究竟做错了什么? 这是我的规范:

var createController,service scope;
beforeEach(inject(function($rootScope, $controller,$injector){
    service = $injector.get('service ');
    scope = $rootScope.$new();
    createController = function() {
        return $controller('controller', {
            '$scope': scope
        });
        spyOn(service , ['redirect']).andCallThrough();
    };
}));

describe('test if service is called', function() {
    it('should call the service', function() {
        var controller=createController();
        scope.goToPage();
        expect(service.redirect).toHaveBeenCalled();
    });
});

});

1 个答案:

答案 0 :(得分:3)

首先,在调用return后定义了间谍,以便永远不会运行代码。其次,在测试中定义你的间谍,而不是在beforeEach中。

var createController,service scope;
beforeEach(inject(function($rootScope, $controller,$injector){
    service = $injector.get('service ');
    scope = $rootScope.$new();
    createController = function() {
        return $controller('controller', {
            '$scope': scope
        });    
    };
}));

describe('test if service is called', function() {
    it('should call the service', function() {
        var controller=createController();
        spyOn(service , ['redirect']).andCallThrough();
        scope.goToPage();
        expect(service.redirect).toHaveBeenCalled();
    });
});