我想将<div id="container">
<!-- ADD AS MANY IMAGE AS YOU LIKE HERE IN REVERSE ORDER -->
<!-- NIGHT -->
<div class="bg" id="night" style="background-image:url(http://i.imgur.com/JK3hIxi.gif);"></div>
<img class="drag" id="moon" src="http://i.imgur.com/VmFEwrH.png">
<!-- EVENING -->
<div class="bg" id="evening" style="background-image:url(http://i.imgur.com/9UqDlgv.png)"></div>
<img class="drag" id="dark_sun" src="http://i.imgur.com/f3UFHb7.png">
<!-- DAY -->
<div class="bg" id="day" style="background-image:url(http://i.imgur.com/aZty7Mq.png)"></div>
<img class="drag" id="sun" src="http://i.imgur.com/DGkZYZQ.png">
</div>
<script src="//code.jquery.com/jquery-1.10.2.js"></script>
<script src="//code.jquery.com/ui/1.11.4/jquery-ui.js"></script>，address和state打印在一个country中。
这就是我调用列值的方法：
echo答案 0 :(得分：2)
你可以连接它们：
echo $userRow['address'] . ', ' $userRow['state'] . ', ' . $userRow['country'];
您可以使用字符串替换：
echo "{$userRow['address']}, {$userRow['state']}, {$userRow['country']}";
您可以使用printf：
printf ("%s, %s, %s", $userRow['address'], $userRow['state'], $userRow['country']);