Question

如何使用Automapper将公共财产Source.Name映射到私有属性Destination.Name。

public class Source
{
    public string Name { get; set; }
}


public class Destination
{
    private string Name { get; set; }
}

Answer 1

尝试使用这个：

Mapper.Initialize(cfg =>
          {
            cfg.ShouldMapProperty = pi => pi.PropertyType.IsPublic || pi.PropertyType.IsNotPublic;
        });

Answer 2

此解决方案创建假lambda表达式。在此示例中，它创建(Destination) => Destination.Name lambda。

Mapper.CreateMap<Source, Destination>()
    .ForMember(CreateMemberLambda<Destination>("Name"), mo => mo.MapFrom(sm => sm.Name));

var source = new Source() { Name = "foo" };
var destination = Mapper.Map<Destination>(source);

public Expression<Func<T, object>> CreateMemberLambda<T>(string parameterName)
{
    var type = typeof(T);
    var bindFlags = BindingFlags.Instance | BindingFlags.Public | BindingFlags.NonPublic;

    var parameter = type.GetProperty(parameterName, bindFlags);
    var classExpression = Expression.Parameter(type, type.Name);
    var memberAccessExpression = Expression.MakeMemberAccess(classExpression, parameter);

    var lambda = Expression.Lambda<Func<T, object>>(memberAccessExpression, classExpression);

    return lambda;
}

Answer 3

我知道这篇文章已经很老了，但我发现了同样的问题，并修改了MaciejLisCK公开的CreateMemberLambda方法对我有用。

public Expression<Func<T, object>> CreateMemberLambda<T>(string parameterName)
    {
        var type = typeof(T);
        var bindFlags = BindingFlags.Instance | BindingFlags.Public | BindingFlags.NonPublic | BindingFlags.GetField;

        var parameter = type.GetField(parameterName, bindFlags);
        var classExpression = Expression.Parameter(type, type.Name);
        var memberAccessExpression = Expression.MakeMemberAccess(classExpression, parameter);

        var lambda = Expression.Lambda<Func<T, object>>(memberAccessExpression, classExpression);

        return lambda;
    }

如何使用AutoMapper将某些属性映射到私有属性

3 个答案: