Question

对于以下Google JSON-LD结构......

<script type="application/ld+json" id="datablock-1">
{
  "@context": "http://schema.org/",
  "@type": "Person",
  "honorificPrefix": "Dr",
  "givenName": "Albert",
  "familyName": "Einstein",
  "honorificSuffix": "PhD",
  "jobTitle": "Professor of Physics",
  "worksFor": [ {
      "@type": "EducationalOrganization",
      "department": "School of Science",
      "parentOrganization": "Princeton University",
      "address": [ {
          "@type": "PostalAddress",
          "streetAddress": "One Relativity Way",
          "addressCountry": "USA" } ]
    } ]
}
</script>

此HTML + JavaScript有效：

<body>
    <dl><dt>Big Ideas</dt><dd id="dd-1"></dd></dl>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
    var data = $("#datablock-1").html();
    var json = JSON.parse(data);
    var people = json["worksFor"];
    for (i=0; i<=people.length; i++) {
        var a=json["givenName"];
        var b=json["familyName"];
        var c=json["honorificSuffix"];
        var d=json["worksFor"][i]["parentOrganization"];
        $('#dd-1').append("<dd>"+a+" "+b+", "+c+". "+" "+d+"."+" "+"</dd>");
    }
</script>
</body>

现在，我需要在对象中更深入一级，并添加有关"@type": "PostalAddress"的信息。

但是这HTML + JavaScript不起作用：

<body>
    <dl><dt>Big Ideas</dt><dd id="dd-1"></dd></dl>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
    var data = $("#datablock-1").html();
    var json = JSON.parse(data);
    var people = json["worksFor"]["address"];
    for (i=0; i<=people.length; i++) {
        var a=json["givenName"];
        var b=json["familyName"];
        var c=json["honorificSuffix"];
        var d=json["worksFor"][i]["parentOrganization"];
        var e=json["worksFor"]["address"][i]["streetAddress"];
        $('#dd-1').append("<dd>"+a+" "+b+", "+c+". "+" "+d+"."+" "+e+"</dd>");
    }
</script>
</body>

我做错了什么？如何纠正错误？

Answer 1

此行失败：

people = json["worksFor"]["address"]

您最终people为undefined，原因是json["worksFor"]为您提供数组。

Answer 2

你不会在不改变条件的情况下从顶部跳到邮政地址吗？我已将android:configChanges="keyboardHidden|orientation|screenSize"变量名称更改为setRetainInstance(true)，因为这是您正在迭代的内容，因为它看起来没有人员列表。也许我错了？

people

Answer 3

这对我很有用......

var json  = {
  "@context": "http://schema.org/",
  "@type": "Person",
  "honorificPrefix": "Dr",
  "givenName": "Albert",
  "familyName": "Einstein",
  "honorificSuffix": "PhD",
  "jobTitle": "Professor of Physics",
  "worksFor": [ {
      "@type": "EducationalOrganization",
      "department": "School of Science",
      "parentOrganization": "Princeton University",
      "address": [ {
          "@type": "PostalAddress",
          "streetAddress": "One Relativity Way",
          "addressCountry": "USA" } ]
    } ]
}


json = JSON.parse(json);

json.worksFor[0].address[0]["@type"].PostalAddress.address = 'streetAddress'

如何在Javascript和HTML中格式化JSON？

3 个答案: