我使用此代码缩放和更改imageview的位置。一个图像视图是稳定的,一个是通过触摸进行缩放和移动。我想合并它们但是当两个图像合并时,第一个图像位于她的第一个位置,第一个尺寸在缩放之前。如何将它们与新的大小和位置合并?
//and below is the brightIt func
public static ColorMatrixColorFilter brightIt(int fb) {
ColorMatrix cmB = new ColorMatrix();
cmB.set(new float[] {
1, 0, 0, 0, fb,
0, 1, 0, 0, fb,
0, 0, 1, 0, fb,
0, 0, 0, 1, 0 });
ColorMatrix colorMatrix = new ColorMatrix();
colorMatrix.set(cmB);
//Canvas c = new Canvas(b2);
//Paint paint = new Paint();
ColorMatrixColorFilter f = new ColorMatrixColorFilter(colorMatrix);
//paint.setColorFilter(f);
return f;
}
public boolean onTouch(View v, MotionEvent event) {
// handle touch events here
ImageView view = (ImageView) v;
switch (event.getAction() & MotionEvent.ACTION_MASK) {
case MotionEvent.ACTION_DOWN:
savedMatrix.set(matrix);
start.set(event.getX(), event.getY());
mode = DRAG;
lastEvent = null;
break;
case MotionEvent.ACTION_POINTER_DOWN:
oldDist = spacing(event);
if (oldDist > 10f) {
savedMatrix.set(matrix);
midPoint(mid, event);
mode = ZOOM;
}
lastEvent = new float[4];
lastEvent[0] = event.getX(0);
lastEvent[1] = event.getX(1);
lastEvent[2] = event.getY(0);
lastEvent[3] = event.getY(1);
d = rotation(event);
break;
case MotionEvent.ACTION_UP:
case MotionEvent.ACTION_POINTER_UP:
mode = NONE;
lastEvent = null;
break;
case MotionEvent.ACTION_MOVE:
if (mode == DRAG) {
matrix.set(savedMatrix);
float dx = event.getX() - start.x;
float dy = event.getY() - start.y;
matrix.postTranslate(dx, dy);
} else if (mode == ZOOM) {
float newDist = spacing(event);
if (newDist > 10f) {
matrix.set(savedMatrix);
float scale = (newDist / oldDist);
matrix.postScale(scale, scale, mid.x, mid.y);
}
if (lastEvent != null && event.getPointerCount() == 2) {
newRot = rotation(event);
float r = newRot - d;
float[] values = new float[9];
matrix.getValues(values);
float tx = values[2];
float ty = values[5];
float sx = values[0];
float xc = (view.getWidth() / 2) * sx;
float yc = (view.getHeight() / 2) * sx;
matrix.postRotate(r, tx + xc, ty + yc);
}
}
break;
}
view.setImageMatrix(matrix);
return true;
}
/**
* Determine the space between the first two fingers
*/
private float spacing(MotionEvent event) {
float x = event.getX(0) - event.getX(1);
float y = event.getY(0) - event.getY(1);
return FloatMath.sqrt(x * x + y * y);
}
/**
* Calculate the mid point of the first two fingers
*/
private void midPoint(PointF point, MotionEvent event) {
float x = event.getX(0) + event.getX(1);
float y = event.getY(0) + event.getY(1);
point.set(x / 2, y / 2);
}
/**
* Calculate the degree to be rotated by.
*
* @param event
* @return Degrees
*/
private float rotation(MotionEvent event) {
double delta_x = (event.getX(0) - event.getX(1));
double delta_y = (event.getY(0) - event.getY(1));
double radians = Math.atan2(delta_y, delta_x);
return (float) Math.toDegrees(radians);
}
答案 0 :(得分:0)
我找到了答案: 我在mergeBitmaps类中使用了ontouch类的矩阵。 background是一个可以拖动,缩放和旋转的imageview。所以在线:
canvas.drawBitmap(stickerBitmap, matrix, null);
我使用ontouch矩阵将位图设置在正确的位置。 在imageview上这里是稳定的,只有背景可以拖动......
public Bitmap mergeBitmaps() {
Bitmap baseBitmap = ((BitmapDrawable) on.getDrawable()).getBitmap();
Bitmap mergedBitmap = Bitmap.createBitmap(baseBitmap.getWidth(), baseBitmap.getHeight(), baseBitmap.getConfig());
Canvas canvas = new Canvas(mergedBitmap);
canvas.drawBitmap(baseBitmap, new Matrix(), null);
Bitmap stickerBitmap = ((BitmapDrawable) background.getDrawable()).getBitmap();
canvas.drawBitmap(stickerBitmap, matrix, null);
canvas.drawBitmap(baseBitmap, new Matrix(), null);
return mergedBitmap;
}