命令行参数分段错误

Question

int main(int argc, const char * argv[]) {

    int first_arg, second_arg; 

    if( argv[1] == NULL || argv[2] == NULL ){
        printf("no arguments! ");
        exit(0);
    }
    else{
        printf("%s  %s \n", argv[1], argv[2] );
        sscanf (argv[1], "%d", &first_arg);
        sscanf (argv[2], "%d", &second_arg);
        printf("%d  %d", first_arg, second_arg);
    }
}

我试图获取int参数。程序适用于少量参数但是当我写大数字时它会给出分段错误。我试图用gdb修复它，它说：

warning: `/private/var/tmp/libplatform/libplatform-24.90.1~2/libplatform.build/libsystem_platform.build/Objects-normal/x86_64/init.o': can't open to read symbols: No such file or directory.
no arguments! [Inferior 1 (process 1275) exited normally]

适用于＆＃34; 100和1＆＃34;，＆＃34; 200和1＆＃34;但是＆＃34; 300和1＆＃34;给出了分段错误。也有效＆＃34; 1和1000＆＃34;但是＆＃34; 10和1000＆＃34;再次给出细分。 它只打印第一个printf in else