Question

在应用程序中，每当我尝试检查灰色选项并单击我的按钮时，我的应用程序崩溃。所有其他单选按钮工作完全正常但每当我尝试通过灰色按钮更改布局的背景颜色时，应用程序崩溃。 P.S当我从代码中删除instructionlayout.setBackgroundResource(R.color.grey);时，灰色也工作得很好并且烤了“灰色”。请帮助我在没有应用程序崩溃的情况下如何在我的所有布局上更改背景颜色。

public void setter(View setv)
{
    RelativeLayout instructionlayout = (RelativeLayout)findViewById(R.id.instructionslayout);
    switch(setv.getId())
    {
        case R.id.changecolorbtn:
            int id = SelectedRadioButton();
            switch(id)
            {
                case 1:toost("Original");break;
                case 2:toost("Grey");instructionlayout.setBackgroundResource(R.color.grey);break;//problem is here
                case 3:toost("Red");break;
                case 4:toost("Orange");break;
                case 5:toost("Yellow");break;
                case 6:toost("Green");break;
                case 7:toost("Aqua");break;
                case 8:toost("Marine");break;
                case 9:toost("Purple");break;
                case 10:toost("Silver");break;
                default:toost("Error! - Select An Option!");
            }
            break;
    }
}
public int SelectedRadioButton()
{
    RadioButton original = (RadioButton)findViewById(R.id.origcolor);
    RadioButton grey = (RadioButton)findViewById(R.id.grey);
    RadioButton red = (RadioButton)findViewById(R.id.red);
    RadioButton orange = (RadioButton)findViewById(R.id.orange);
    RadioButton yellow = (RadioButton)findViewById(R.id.yellow);
    RadioButton green = (RadioButton)findViewById(R.id.green);
    RadioButton aqua = (RadioButton)findViewById(R.id.aqua);
    RadioButton marine = (RadioButton)findViewById(R.id.marine);
    RadioButton purple = (RadioButton)findViewById(R.id.purple);
    RadioButton silver = (RadioButton)findViewById(R.id.silver);
    int starter = 1;
    switch(starter)//take advantage of switch falling without break statement
    {
        case 1:if(original.isChecked()){return 1;}
        case 2:if(grey.isChecked()){return 2;}
        case 3:if(red.isChecked()){return 3;}
        case 4:if(orange.isChecked()){return 4;}
        case 5:if(yellow.isChecked()){return 5;}
        case 6:if(green.isChecked()){return 6;}
        case 7:if(aqua.isChecked()){return 7;}
        case 8:if(marine.isChecked()){return 8;}
        case 9:if(purple.isChecked()){return 9;}
        case 10:if(silver.isChecked()){return 10;}
    }
    return -1;//if nothing is checked
}

colors.xml：

<resources>
<color name="original">#25383C</color>
<color name="grey">#484849</color>
<color name="red">#881A27</color>
<color name="orange">#ffa500</color>
<color name="yellow">#CDE707</color>
<color name="green">#00ff00</color>
<color name="aqua">#00FFCC</color>
<color name="marine">#0C0C84</color>
<color name="purple">#630A86</color>
<color name="silver">#c0c0c0</color>
</resources>

logcat的：

10-22 10:32:49.834  17834-17834/dhruvyadav.msplit E/AndroidRuntime﹕ FATAL EXCEPTION: main
Process: dhruvyadav.msplit, PID: 17834
java.lang.IllegalStateException: Could not execute method of the activity
        at android.view.View$1.onClick(View.java:3983)
        at android.view.View.performClick(View.java:4654)
        at android.view.View$PerformClick.run(View.java:19438)
        at android.os.Handler.handleCallback(Handler.java:733)
        at android.os.Handler.dispatchMessage(Handler.java:95)
        at android.os.Looper.loop(Looper.java:146)
        at android.app.ActivityThread.main(ActivityThread.java:5602)
        at java.lang.reflect.Method.invokeNative(Native Method)
        at java.lang.reflect.Method.invoke(Method.java:515)
        at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1283)
        at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1099)
        at dalvik.system.NativeStart.main(Native Method)
 Caused by: java.lang.reflect.InvocationTargetException
        at java.lang.reflect.Method.invokeNative(Native Method)
        at java.lang.reflect.Method.invoke(Method.java:515)
        at android.view.View$1.onClick(View.java:3978)

我试过了：

 View instructionlayout = (View)findViewById(R.id.instructionslayout);
 instructionlayout.setBackgroundColor(R.color.grey);

如何在我的.setBackground代码之间放置一个ui线程？

Answer 1

你使用setBackgroundColor

yourView.setBackgroundColor(R.color.your_color);

Answer 2

使用它：

instructionlayout.setBackgroundColor(Color.GRAY);

而不是：

instructionlayout.setBackgroundResource(R.color.grey);

Answer 3

试试这个

int color = getResources().getColor(R.color.original);
instructionlayout.setBackgroundColor(color);

或

instructionlayout.setBackgroundResource(R.color.original);

Answer 4

请检查RelativeLayout的ID是否与您引用的ID相同。

R.id.instructionslayout可以像对象名一样R.id.instructionlayout。

Answer 5

请使用以下代码..它对我有用..我希望它能帮到你......

使用此

instructionlayout.setBackgroundColor（getResources（）的getColor（R.color.white））;

而不是

instructionlayout.setBackgroundResource（R.color.grey）;

.setBackgroundResource崩溃我的应用程序

5 个答案: