我在Spring 4.2.0中创建了自定义login form
和create new account
表单。他们工作得很好。但是现在我已经为新创建的用户实现了自动登录,该用户成功登录了创建的用户。但是,如果我注销并尝试使用相同的凭据再次登录,则身份验证将失败。并且身份验证对其他用户也不起作用。因此,用户能够登录的唯一时间是创建时间。之后认证失败。让我认为自动登录代码由于某种原因破坏了春季登录认证。看看下面的代码。有人猜到为什么会这样吗?
登录表单:
<form:form modelAttribute="loginForm" action="${pageContext.request.contextPath}/login" method="POST">
Username:<form:input path="username" size="30" />
Password:<form:password path="password" size="30" />
<input type="submit" value="Login" />
</form:form>
安全配置:
<security:http auto-config="true" use-expressions="true">
<security:form-login default-target-url="/home" login-page="/"
authentication-failure-url="/?error=true" />
<security:intercept-url pattern="/" access="permitAll" />
<security:intercept-url pattern="/newaccount"
access="permitAll" />
<security:intercept-url pattern="/createAccount/**"
access="isAnonymous()" />
<security:intercept-url pattern="/login"
access="permitAll" />
<security:intercept-url pattern="/logout"
access="permitAll" />
<security:intercept-url pattern="/home"
access="isAuthenticated()" />
<security:intercept-url pattern="/**" access="denyAll" />
<security:csrf disabled="true" />
<security:logout />
</security:http>
<security:authentication-manager id="authManager">
<security:authentication-provider>
<security:jdbc-user-service data-source-ref="dataSource" />
<security:password-encoder ref="passwordEncoder"></security:password-encoder>
</security:authentication-provider>
</security:authentication-manager>
<bean id="passwordEncoder"
class="org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder">
</bean>
插入数据库之前的密码加密:
user.setPassword(passwordEncoder.encode(newAccountDetails.getPassword()));
成功创建用户后在控制器中自动登录:
@RequestMapping("/createAccount")
public ModelAndView submitCreateAccount(@ModelAttribute("newAccount") NewAccountDetails newAccountDetails) {
System.out.println(newAccountDetails);
ModelAndView mv = new ModelAndView();
if (userServices.createUserService(newAccountDetails)) {
System.out.println("user created successfully");
try {
userDetails = userDetailService.loadUserByUsername(newAccountDetails.getUsername());
System.out.println(userDetails);
UsernamePasswordAuthenticationToken authToken = new UsernamePasswordAuthenticationToken(userDetails,
newAccountDetails.getPassword(), userDetails.getAuthorities());
authManager.authenticate(authToken);
if (authToken.isAuthenticated()) {
System.out.println("New User is authenticated");
SecurityContextHolder.getContext().setAuthentication(authToken);
mv.setViewName("redirect:/home");
} else {
System.out.println("user not authenticated.");
mv.setViewName("redirect:/");
}
} catch (Exception e) {
System.err.println("e: " + e);
mv.setViewName("redirect:/");
}
} else {
System.out.println("user not created");
mv.setViewName("redirect:/newaccount");
}
return mv;
}
答案 0 :(得分:0)
您使用特定url
定义了自己的AuthenticationManager
。但是,Spring Security对此特定实例一无所知,仍然使用默认的id
。因此,对于注册和登录,您基本上使用authenticationManager
的2个不同实例。
要解决此问题,您需要告诉Spring Security要使用哪个,通过将AuthenticationManager
属性添加到主authentication-manager-ref
元素来执行此操作。
http
或通过自己<security:http auto-config="true" use-expressions="true" authentication-manager-ref="<your-authetnication-manager-id>">
指定alias
。
AuthenticationManager
有关详细信息,请参阅http://docs.spring.io/spring-security/site/docs/current/reference/htmlsingle/#ns-auth-manager。