Question

情况

我有一个系统，其中一个请求产生两个响应。请求和响应具有相应的可观察量：

IObservable<RequestSent> _requests;
IObservable<MainResponseReceived> _mainResponses;
IObservable<SecondResponseReceived> _secondaryResponses;

保证RequestSent事件早于MainResponseReceived和SecondaryResponseReceived，但响应按随机顺序排列。

我拥有什么

最初我想要处理两个响应的处理程序，所以我压缩了observables：

_requests
    .SelectMany(async request =>
    {
        var main = _mainResponses.FirstAsync(m => m.Id == request.Id);
        var secondary = _secondaryResponses.FirstAsync(s => s.Id == request.Id);

        var zippedResponse = main.Zip(secondary, (m, s) => new MainAndSecondaryResponseReceived {
            Request = request,
            Main = m, 
            Secondary = s
        });
        return await zippedResponse.FirstAsync(); ;
    })
    .Subscribe(OnMainAndSecondaryResponseReceived);

我需要什么

现在我还需要处理MainResponseReceived而不等待SecondaryResponseRecieved，并且必须保证，OnMainResponseRecieved在调用OnMainAndSecondaryResponseReceived之前完成

如何定义这两个订阅？

测试案例1：

RequestSent
MainResponseReceived发生 - ＆gt; OnMainResponseReceived被称为
SecondaryResponseReceive d出现 - ＆gt; OnMainAndSecondaryResponseReceived被称为

测试案例2：

RequestSent
SecondaryResponseReceived
MainResponseReceived occurs - ＆gt; OnMainResponseReceived被称为 - ＆gt; OnMainAndSecondaryResponseReceived被称为

Answer 1

我认为你几乎走在正确的轨道上。我会停止使用所有Async的东西 - 这只是让事情变得复杂。

尝试此查询：

var query =
    _requests
        .SelectMany(request =>
            _mainResponses.Where(m => m.Id == request.Id).Take(1)
                .Do(m => OnMainResponseReceived(m))
                .Zip(
                    _secondaryResponses.Where(s => s.Id == request.Id).Take(1),
                    (m, s) => new MainAndSecondaryResponseReceived()
                    {
                        Request = request,
                        Main = m, 
                        Secondary = s
                    }));

var subscription =
    query.Subscribe(x => OnMainAndSecondaryResponseReceived(x));

.Do(...)是代码中重要的缺失部分。它确保在OnMainResponseReceived之前调用OnMainAndSecondaryResponseReceived，无论主要或次要响应是否首先出现。

我测试了这个：

Subject<RequestSent> _requestsSubject = new Subject<RequestSent>();
Subject<MainResponseReceived> _mainResponsesSubject = new Subject<MainResponseReceived>();
Subject<SecondResponseReceived> _secondaryResponsesSubject = new Subject<SecondResponseReceived>();

IObservable<RequestSent> _requests = _requestsSubject.AsObservable();
IObservable<MainResponseReceived> _mainResponses = _mainResponsesSubject.AsObservable();
IObservable<SecondResponseReceived> _secondaryResponses = _secondaryResponsesSubject.AsObservable();

_requestsSubject.OnNext(new RequestSent() { Id = 42 });
_mainResponsesSubject.OnNext(new MainResponseReceived() { Id = 42 });
_secondaryResponsesSubject.OnNext(new SecondResponseReceived() { Id = 42 });

_requestsSubject.OnNext(new RequestSent() { Id = 99 });
_mainResponsesSubject.OnNext(new MainResponseReceived() { Id = 99 });
_secondaryResponsesSubject.OnNext(new SecondResponseReceived() { Id = 99 });

使用被动扩展以正确的顺序处理多个响应

情况

我拥有什么

我需要什么

1 个答案: