Question

我正在以下列方式验证我的用户

<?php

namespace App\Http\Controllers;

use Illuminate\Http\Request;
use Illuminate\Support\Facades\Auth;
use App\Http\Requests;
use App\Http\Controllers\Controller;
use Illuminate\Support\Facades\Input;
use App\User;
use Session;
use Validator;

class CollectionloginController extends Controller
{
    /**
     * Display a listing of the resource.
     *
     * @return Response
     */
    public function getIndex(){
        return View('collectionmodule/login');
    }

    public function postCollectionlogin(){

            $rules = array(

           'email'=>'required',
            'password'=>'required'

            );

            $validator = Validator::make(Input::all(), $rules);

            if ($validator->fails())
            {
                return redirect('collection/login')->withErrors($validator);

            }else {

                  $cred = array(
                        'email' => Input::get('email'),
                        'password' => Input::get('password')
                    );

                $role = User::where('email','=',Input::get('email'))->first();

                if (Auth::attempt($cred) && $role->role == 'collector'){
                    if (Auth::check()){
                        Session::put('role','collector');
                        Session::put('name',Auth::user()->name);
                        return redirect('collection/home');
                    }

                } 
                else{
                        Session::flush();
                        Auth::logout();
                        return redirect('collection/login')->with('login_errors',true);
            }
        }


    }

}

和我的路线是

//Collection started by vikram
Route::controller('collection/login','CollectionloginController');
Route::controller('collection/home','CollectionController');

Route::get('collection', function () {
    return view('collectionmodule.login');
});

Route::get('collection/logout',function(){
    Session::flush();
    Auth::logout();
    return Redirect::to('collection/target');
});

控制器是

命名空间App \ Http \ Controllers;

use Illuminate\Http\Request;
use Illuminate\Support\Facades\Auth;
use App\Http\Requests;
use App\Http\Controllers\Controller;
use Illuminate\Support\Facades\Input;
use App\User;

class CollectionController extends Controller
{
    /**
     * Display a listing of the resource.
     *
     * @return Response
     */

  public function getIndex(){

    $empid= Auth::user()->empid;
    $invoice = Invoice::orderBy('Id', 'desc')->get();


    return View('collectionmodule/home')->with(array('invoices'=>$invoice));
}
}

我的问题是如何在访问任何函数之前验证类collectionContorller，就像经过身份验证的用户不是收集器一样，它应该重定向回登录页面

我也遇到类似的问题

我想到的一种方法是这样的

  public function __construct(){
          if(Session::get('role')!="collector"){
          $validotrs= "The User is not a collector";
        return redirect('collection/login')->withErrors($validator);
}
    }

任何人都可以帮助我

Answer 1

您不应手动设置会话。如果用户已登录，您可以通过Auth外观访问它，如下所示：Auth::user()。

但基本上，如果要在处理请求之前检查当前的身份验证设置或其他任何设置，则应使用Middleware。

php artisan make:middleware Collector

在App\Http\Middleware\Collector下新创建的文件中，您可以更改handle函数来表示您的逻辑：

public function handle($request, Closure $next)
{
    if (Session::get('role') != "collector")
        return redirect('collection/login');

    // Alternatively, using Auth Facade

    if ($request->user()->role != 'collector')
        return redirect('collection/login');

    return $next($request);
}

现在您必须在App\Http\Kernel.php数组的$routeMiddleware中注册中间件。

'collector' => \App\Http\Middleware\Collector::class,

在您的收藏家 - 控制器中，您现在可以像这样引用它：

public function __construct()
{
    $this->middleware('collector');
}

在每次向控制器发出请求时，collector中间件都会被检查并执行您定义的逻辑。

修改

如果您需要动态中间件，它看起来像这样：

# /App/Http/Middlware/Role.php public function handle($request, Closure $next, $role) { if ($request->user()->role != $role) return redirect('collection/login'); return $next($request); }

在你的控制器中：

public function __construct() { $this->middleware('role:collector'); // replace 'collector' with whatever role you need. }

如何在访问之前验证Laravel 5中的类

1 个答案: