Question

嗨，我无法解决这个问题，

我跟着http://blackglasses.me/2013/09/17/custom-django-user-model/ 教程。

我无法回忆，但我想我在某处读到如果你使用功能性视图，你必须输入一些东西，但不确定这是否是这种情况，或者是否属实。

以下是我在帐户应用中的urls.py代码

from django.conf.urls import patterns, url
from accounts import views

urlpatterns = patterns(
   url(r'^register$', 'accounts.views.register', name='register'),
   url(r'^login$', 'accounts.views.login', name='login'),
   url(r'^logout$', 'accounts.views.logout', name='logout'),

）

主urls.py

from django.conf.urls import patterns, include, url
from django.contrib import admin

urlpatterns = ['',
    url(r'^accounts/', include('accounts.urls', namespace='accounts')),
    url(r'^admin/', include(admin.site.urls)),
  ]

以下是错误消息和追溯

Environment:
Django Version: 1.8.5
Python Version: 3.4.0

Request Method: GET
Request URL: http://127.0.0.1:8777/

Django Version: 1.8.5
Python Version: 3.4.0


Request Method: GET
Request URL:    http://127.0.0.1:8777/
Django Version: 1.8.5
Exception Type: TypeError
Exception Value:    
unsupported operand type(s) for +: 'RegexURLPattern' and 'str'
Exception Location: /home/kevin/djangoP/envRU/lib/python3.4/site-packages/django/core/urlresolvers.py in add_prefix, line 223
Python Executable:  /home/kevin/djangoP/envRU/bin/python
Python Version: 3.4.0


Traceback:

    File "/home/kevin/djangoP/envRU/lib/python3.4/site-packages/django/core/handlers/base.py" in get_response
      119.                 resolver_match = resolver.resolve(request.path_info)

    File "/home/kevin/djangoP/envRU/lib/python3.4/site-packages/django/core/urlresolvers.py" in resolve
      365.             for pattern in self.url_patterns:


    File "/home/kevin/djangoP/envRU/lib/python3.4/site-packages/django/core/urlresolvers.py" in url_patterns
      401.         patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)

    File "/home/kevin/djangoP/envRU/lib/python3.4/site-packages/django/core/urlresolvers.py" in urlconf_module
      395.             self._urlconf_module = import_module(self.urlconf_name)

    File "/home/kevin/djangoP/envRU/lib/python3.4/importlib/__init__.py" in import_module
      109.     return _bootstrap._gcd_import(name[level:], package, level)

    File "/home/kevin/djangoP/ru/rulinked/rulinked/urls.py" in <module>
      20.     url(r'^accounts/', include('accounts.urls', namespace='accounts')),


    File "/home/kevin/djangoP/envRU/lib/python3.4/site-packages/django/conf/urls/__init__.py" in include
      33.         urlconf_module = import_module(urlconf_module)


    File "/home/kevin/djangoP/envRU/lib/python3.4/importlib/__init__.py" in import_module
      109.     return _bootstrap._gcd_import(name[level:], package, level)


    File "/home/kevin/djangoP/ru/rulinked/accounts/urls.py" in <module>
      7.     url(r'^logout$', 'accounts.views.logout', name='logout'),

    File "/home/kevin/djangoP/envRU/lib/python3.4/site-packages/django/conf/urls/__init__.py" in patterns
      61.             t.add_prefix(prefix)

    File "/home/kevin/djangoP/envRU/lib/python3.4/site-packages/django/core/urlresolvers.py" in add_prefix
      223.         self._callback_str = prefix + '.' + self._callback_str

    Exception Type: TypeError at /
    Exception Value: unsupported operand type(s) for +: 'RegexURLPattern' and 'str'

如果你读到那么远，那么谢谢你，我知道它很多，但我真的迷路了，不知道还能在哪里得到帮助。

Answer 1

您会混淆两种可用的语法。

patterns()函数将前缀作为第一个参数，它是一个（可能为空）字符串，并返回一个列表，其中前缀添加到每个模式。其他参数是url()个实例。普通列表应该只包含url()个实例，并且您无法添加公共前缀。

patterns()已被弃用，因此最好在任何地方使用列表：

账户/ urls.py

urlpatterns = [
   url(r'^register$', 'accounts.views.register', name='register'),
   url(r'^login$', 'accounts.views.login', name='login'),
   url(r'^logout$', 'accounts.views.logout', name='logout'),
]

urls.py

urlpatterns = [
    url(r'^accounts/', include('accounts.urls', namespace='accounts')),
    url(r'^admin/', include(admin.site.urls)),
]

对于导入视图：如果传递函数本身，则需要导入它们。如果您不先导入，则该功能不可用，并生成NameError。现在你正在通过导入路径，而不是功能，所以你不必导入任何东西。这也被弃用（对于视图，不包括其他url配置），因此为了与未来的Django版本兼容，您可以将其更改为：

from django.conf.urls import url
from accounts import views

urlpatterns = [
   url(r'^register$', views.register, name='register'),
   url(r'^login$', views.login, name='login'),
   url(r'^logout$', views.logout, name='logout'),
]

请注意，url()的第二个参数不再是字符串，而是导入的views模块中的视图函数本身。

Answer 2

将您的app urls.py编辑为：

from django.conf.urls import patterns, url
from accounts import views

urlpatterns = patterns('', // add the empty string here
   url(r'^register$', 'accounts.views.register', name='register'),
   url(r'^login$', 'accounts.views.login', name='login'),
   url(r'^logout$', 'accounts.views.logout', name='logout'),
)

另外，从主urls.py中删除空字符串：

from django.conf.urls import patterns, include, url
from django.contrib import admin

urlpatterns = [
    url(r'^accounts/', include('accounts.urls', namespace='accounts')),
    url(r'^admin/', include(admin.site.urls)),
  ]

因为我不认为在使用方括号版本时需要它。

+：＆＃39; RegexURLPattern＆＃39;不支持的操作数类型和＆＃39; str＆＃39;

2 个答案: