我试图让代码找到用户输入的因子,为用户的输入提供素数分解,并给出lcm和gcm。它应该很简单。它是一个编程简介类,但它对我来说太快了。我花了好几个小时阅读和学习,并试图让这些代码工作。请帮忙。
import java.util.Scanner;
public class PattersonFactorization {
public static void main(String[] args)
{
//create scanner to obtain input from command window
Scanner input = new Scanner(System.in);
//initialization phase
int input1 = 0; //initialize first input from user
int input2 = 0; //initialize second input from user
//prompt twice for two inputs from user
//until they enter a positive value for each input
do
{
System.out.println("Please provide your first positive number: ");
input1 = input.nextInt();
}//end do for input1
while(input1 <= 0);
do
{
System.out.println("Please provide your next positive number: ");
input2 = input.nextInt();
}//end do for input2
while(input2 <= 0);
// call methods for factorization calculations
calculateFactors(input1);
calculateFactors(input2);
calculatePrime(input1);
calculatePrime(input2);
calculateLCM(input1, input2);
calculateGCF(input1, input2);
}//end of main
public static void calculateFactors(int input)
{
for(int countFactor = 1; countFactor < input; countFactor++)
{
if(countFactor % input == 0);
System.out.println(countFactor);
}
}//end of calculateFactors
public static void calculatePrime(int input)
{
for(int countPrime = 1; countPrime < input; countPrime++)
{
if(countPrime % input == 0);
System.out.println(countPrime);
input = input/countPrime;
countPrime--;
}
}//end of calculatePrime
public static void calculateLCM(int input1, int input2)
{
for(int factorNum = 1; input1 % factorNum != 0 && input2 % factorNum != 0; factorNum++)
System.out.println(factorNum);
}//end of calculateLCM
public static void calculateGCF(int input1, int input2)
{
for(int factorNum = input1; input1 % factorNum != 0 && input2 % factorNum != 0; factorNum--)
System.out.println(factorNum);
}
}//end of class
`
答案 0 :(得分:2)
我认为问题在于:
for(int countPrime = 1; countPrime < input; countPrime++)
{
if(countPrime % input == 0);
System.out.println(countPrime);
input = input/countPrime;
countPrime--;
}
递增循环递减 countPrime
。结果它永远不会改变它的价值。
答案 1 :(得分:0)
您的代码存在一些问题:
if(countFactor % input == 0);
System.out.println(countFactor);
无论条件表达式的值如何,此处的代码始终会执行System.out.println(countFactor);
。问题是if(countFactor % input == 0);
- 您的if
在结尾处有分号。
if(countFactor % input == 0)
System.out.println(countFactor);
但是对于编码器来说,使用大括号几乎总是更清楚,编译器会显示范围:
if(countFactor % input == 0) {
System.out.println(countFactor);
}
您的无限循环来自countPrime
循环中递增和递减for
:
for(int countPrime = 1; countPrime < input; countPrime++)
{
if(countPrime % input == 0);
System.out.println(countPrime);
input = input/countPrime;
countPrime--;
}
countPrime
将在循环结束时递减到0
,然后在下一次循环迭代时递增回1
。 input = input/countPrime;
始终为input = input/1
,这是您的终止表达式永远不会true
的另一个原因。