Spring 3带注释的配置获取@Configuration和@Component,但不是@Controller

时间:2010-07-22 19:13:02

标签: java spring spring-mvc controller annotations

所以我正在尝试在没有XML的情况下配置我的Web应用程序并进入所有带注释的路径。我有一些使用@Configuration和@Component注释的类被自动拾取,但由于某种原因,我的@Controller注释未被识别并映射到相应的@RequestMapping值。

我的web.xml文件如下所示:

<?xml version="1.0" encoding="UTF-8"?>
<web-app id="com-timbuk2-webapp-compositor" 
         version="3.0"
         xmlns="http://java.sun.com/xml/ns/javaee" 
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
         xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" 
         xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" >

    <display-name>timbuk2-webapp-Compositor</display-name>

    <!-- Context Parameters -->
    <context-param>
        <param-name>log4jConfigLocation</param-name>
        <param-value>/WEB-INF/conf/log4j-config.xml</param-value>
    </context-param>

    <context-param>
        <param-name>contextClass</param-name>
        <param-value>org.springframework.web.context.support.AnnotationConfigWebApplicationContext</param-value>
    </context-param>

    <context-param>
       <param-name>contextConfigLocation</param-name>
       <param-value>com.company.webapp</param-value>
    </context-param>

    <!-- Listeners -->
    <listener>
        <listener-class>org.springframework.web.util.Log4jConfigListener</listener-class>
    </listener>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <!-- Filters -->
    <filter>
        <filter-name>characterEncodingFilter</filter-name>
        <filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
        <init-param>
            <param-name>encoding</param-name>
            <param-value>UTF-8</param-value>
        </init-param>
        <init-param>
            <param-name>forceEncoding</param-name>
            <param-value>true</param-value>
        </init-param>
    </filter>

    <filter>
        <filter-name>urlRewriteFilter</filter-name>
        <filter-class>org.tuckey.web.filters.urlrewrite.UrlRewriteFilter</filter-class>
        <init-param>
            <param-name>logLevel</param-name>
            <param-value>commons</param-value>
        </init-param>
        <init-param>
            <param-name>confPath</param-name>
            <param-value>/WEB-INF/conf/urlrewrite-config.xml</param-value>
        </init-param>
    </filter>

    <!-- Filter Mappings -->
    <filter-mapping>
        <filter-name>characterEncodingFilter</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>

    <filter-mapping>
        <filter-name>urlRewriteFilter</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>

    <!-- Servlets -->
    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    </servlet>

    <!-- Servlet mappings -->
    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/app/*</url-pattern>
    </servlet-mapping>


</web-app>

我的主要@Configuration类看起来像这样:

package com.company.webapp.config;

import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.context.support.ReloadableResourceBundleMessageSource;
import org.springframework.web.servlet.view.InternalResourceViewResolver;
import org.springframework.web.servlet.view.JstlView;

@Configuration
public class ApplicationConfiguration
{    
    @Bean
    public ReloadableResourceBundleMessageSource messageSource()
    {
        ReloadableResourceBundleMessageSource messageSource = new ReloadableResourceBundleMessageSource();
        messageSource.setBasename( "/WEB-INF/resources/messages" );
        messageSource.setCacheSeconds( 0 );
        return messageSource;
    }

    @Bean
    public InternalResourceViewResolver viewResolver()
    {
        InternalResourceViewResolver viewResolver = new InternalResourceViewResolver();
        viewResolver.setViewClass( JstlView.class );
        viewResolver.setPrefix( "/WEB-INF/views/" );
        viewResolver.setSuffix( ".jsp" );
        return viewResolver;
    }
}

我的@Controller和@Component类都存在于同一个包中。例如,这是我的应用程序中的@Controller类:

package com.company.webapp.controller;

import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.stereotype.Controller;
import org.springframework.validation.BindingResult;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;

@Controller
@RequestMapping( value = "/render" )
public class RenderController
{
    private final Logger logger = LoggerFactory.getLogger( getClass() );

    @RequestMapping( method = RequestMethod.GET )
    public ModelAndView handleGet( BindingResult bindingResult )
    {
        ... eventually return a ModelAndView object...
    }
}

重申一下,我的@Controller类没有映射到我指定的URL。当应用程序启动或在我的本地tomcat环境中重新加载时,我没有看到通常的“映射URL”/渲染“到...”控制台输出。

有人能告诉我我错过了什么可能会阻止我的@Controller注释类无法找到并注册?

3 个答案:

答案 0 :(得分:5)

我想这是因为@Controller应该由DispatcherServlet从其自己的应用程序上下文(默认情况下从<servletname>-servlet.xml加载)中挑选contextClasscontextConfigLocation ContextLoaderListener应用于根上下文(applicationContext.xml的一个,默认情况下从DispatcherServlet加载)。

要配置contextClass应用程序上下文,您应将contextConfigLocationinit-param设置为servlet的detectHandlersInAncestorContexts

修改 此行为由DefaultAnnotationHandlerMapping的属性true控制,因此备用方法是在配置期间将其设置为@Bean public DefaultAnnotationHandlerMapping mapping() { DefaultAnnotationHandlerMapping m = new DefaultAnnotationHandlerMapping(); m.setDetectHandlersInAncestorContexts(true); return m; }

{{1}}

答案 1 :(得分:1)

在你的mvc dispatcher servlet xml文件中添加它,其中包应该是为@controller或@Component扫描的所有控制器。

<context:component-scan
        base-package="packagesseperatedbycomma" />

答案 2 :(得分:1)

我解决了这个问题,但是在我的web.xml中添加了以下代码:

<servlet>
        <servlet-name>Spring MVC Dispatcher Servlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextClass</param-name>
            <param-value>org.springframework.web.context.support.AnnotationConfigWebApplicationContext</param-value>
        </init-param>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>org.xxxx.inquiry.config, org.xxxx.inquiry.controller</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

但这样做我告诉它在哪里寻找我的控制器