我想从代码的实际结构进行更改。这是我的实际代码:
questionList.count().then(function (count) {
var res = count;
});
if (res < 3) ...
现在我想将上面的代码更改为此(请随时告诉我这是否是在Node.js中处理的好方法):
Image img = new Bitmap(1, 1);
Graphics drawing = Graphics.FromImage(img);
我应该如何写上面的//index.js
var routes = require('./routes');
var subdomain = require('express-subdomain');
//require express app with settings
var app = require('./app');
//export the application
module.exports = app;
// routes request like endusers-api.mydomain.ext/
app.use(subdomain('endusers-api', routes.apis.endusers));
// routes request like mydomain.ext/
app.use(routes.webapps.endusers);
//routes/index.js
var apis = {endusers: require("./apis/endusers")}
var webapps = {endusers: require("./webapps/endusers")}
var routes = {apis: apis, webapps: webapps}
module.exports = routes;
//routes/apis/endusers
var express = require('express');
var route = express.Router();
var logger = require('../../lib/logger');
route.get('/', logger("endusers-api-access"), function(req, res, next) {
res.json({
"name" : "Endusers API"
});
});
module.exports = route;
//routes/webapps/endusers.js
var express = require('express');
var route = express.Router();
var logger = require('../../lib/logger');
route.get('/', logger("endusers-webapp-access"), function(req, res, next) {
res.render('endusers/index', {title: 'Homepage'});
});
module.exports = route;
部分。看起来我们需要嵌套的中间件(一个中间件调用另一个中间件)。请你的建议。
答案 0 :(得分:0)
我通过express.Router()。all()方法找到了答案。
//middlewares/apis/endusers.js
var routes = require('../../routes');
var express = require('express');
var middleware = express.Router();
middleware.all('/',subdomain('endusers-api', routes.apis.endusers));
//the two next lines are alternatives to the line above
//middleware = subdomain('endusers-api', routes.apis.endusers); //can assign only one route
//middleware.use(subdomain('endusers-api', routes.apis.endusers)); // can use many routes
module.exports = middleware;
//middlewares/webapps/endusers.js
var routes = require('../../routes');
var express = require('express');
var middleware = express.Router();
middleware.all('/', routes.webapps.endusers);
//the two next lines are alternatives to the line above
//middleware = routes.webapps.endusers; //can assign only one route
//middleware.use(routes.webapps.endusers); // can use many routes
module.exports = middleware;
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