if-else statement
感到有些困惑。我的table layout
中有4行,每行都会检查它是否有价值。
案例1
public void onClick(DialogInterface dialog, int ii)
{
if ((i != null && i.trim().length() > 0))
{
WD.insertWorkDetails(a1, W1, P1, b, c); //row 1
WD.insertWorkDetails(a2, W2, P2, d, e1); //row 2
WD.insertWorkDetails(a3, W3, P3, f, g); //row 3
WD.insertWorkDetails(a4, W4, P4, h, i); //row 4
ts.insertTimeSheet(name, weather, date, status, b, i);
WF.insertWorkForce(subContractors, noPeople, noHours);
Toast.makeText(getApplicationContext(), "4 Row has value", Toast.LENGTH_LONG).show();
}
else if (TextUtils.isEmpty(i) && (g != null && g.trim().length() > 0))
{
if ((TextUtils.isEmpty(W4)) && (TextUtils.isEmpty(P4)) && (TextUtils.isEmpty(h)) && (TextUtils.isEmpty(i)))
{
WD.insertWorkDetails(a1, W1, P1, b, c);
WD.insertWorkDetails(a2, W2, P2, d, e1);
WD.insertWorkDetails(a3, W3, P3, f, g);
ts.insertTimeSheet(name, weather, date, status, b, g);
WF.insertWorkForce(subContractors, noPeople, noHours);
Toast.makeText(getApplicationContext(), "Row 4 no value", Toast.LENGTH_LONG).show();
}
else
{
database = dbHelper.getWritableDatabase();
WD.insertWorkDetails(a1, W1, P1, b, c);
WD.insertWorkDetails(a2, W2, P2, d, e1);
WD.insertWorkDetails(a3, W3, P3, f, g);
WD.insertWorkDetails(a4, W4, P4, h, i);
ts.insertTimeSheet(name, weather, date, status, b, g);
WF.insertWorkForce(subContractors, noPeople, noHours);
Toast.makeText(getApplicationContext(), " All Row has value ",
Toast.LENGTH_LONG).show();
}
}
在案例1中,g!=null
和w4
包含值,但我得Row 4 no value
,假设返回All Row has value
。为什么呢?
案例2
else if (TextUtils.isEmpty(i) && (TextUtils.isEmpty(g) && (TextUtils.isEmpty(e1)) && (c != null && c.trim().length() > 0)))
{
if ((TextUtils.isEmpty(W4)) && (TextUtils.isEmpty(P4))
&& (TextUtils.isEmpty(h)) && (TextUtils.isEmpty(i))
&& ((TextUtils.isEmpty(W3)) && (TextUtils.isEmpty(P3))
&& (TextUtils.isEmpty(f)) && (TextUtils.isEmpty(g)))
&& ((TextUtils.isEmpty(W2)) && (TextUtils.isEmpty(P2))
&& (TextUtils.isEmpty(d)) && (TextUtils.isEmpty(e1))))
{
ts.insertTimeSheet(name, weather, date, status, b, c);
WF.insertWorkForce(subContractors, noPeople, noHours);
WD.insertWorkDetails(a1, W1, P1, b, c);
Toast.makeText(getApplicationContext(), "Row 1 has value only", Toast.LENGTH_LONG).show();
}
else if ((W4 != null && W4.trim().length() > 0))
{
WD.insertWorkDetails(a1, W1, P1, b, c);
WD.insertWorkDetails(a2, W2, P2, d, e1);
WD.insertWorkDetails(a3, W3, P3, f, g);
WD.insertWorkDetails(a4, W4, P4, h, i);
ts.insertTimeSheet(name, weather, date, status, c, b);
WF.insertWorkForce(subContractors, noPeople, noHours);
Toast.makeText(getApplicationContext(), "All row have value", Toast.LENGTH_LONG).show();
}
}
在案例2中,c and W4!=null
,但我得到row 1 has value only
。
答案 0 :(得分:0)
至少必须在代码末尾关闭大括号。
无论如何,我看到了if-s的这种结构:
if(...condition-1...) {
...code-1...
} esle if(...condition-2...) {
if(...condition-3...){
...code-3...
} else {
...code-4...
}
}
也许你想要"否则"使用代码-4来引用"如果"条件-2,而不是"如果"条件-3?然后你会以这种方式改变结构(附加}之前):
if(...condition-1...) {
...code-1...
} esle if(...condition-2...) {
if(...condition-3...){
...code-3...
}
} else {
...code-4...
}
答案 1 :(得分:0)
我认为,if-else语句没有问题。可能是,你得到长度为>的空字符串; 0. TextUtils.isEmpty():如果字符串为null或0-length,则返回true。 http://developer.android.com/reference/android/text/TextUtils.html#isEmpty(java.lang.CharSequence)