Question

我目前正在研究加密程序，并面临使用Python 3编写非文本文件的问题。

例如，这将起作用（定义了fEncode（））：

Public Sub moveRows2()
    Dim ws1 As Worksheet, ws2 As Worksheet, ur1 As Range, xRow2 As Long

    Set ws1 = Worksheets("Sheet1")
    Set ws2 = Worksheets("Sheet2")

    xRow2 = ws2.UsedRange.Row + ws2.UsedRange.Rows.Count    'find 1st blank cell on Sheet2

    Set ur1 = ws1.UsedRange

    With ur1
        .AutoFilter
        .AutoFilter Field:=5, Criteria1:="="       'AutoFilter Col E (blank cells)

        'If there are any visible rows
        If ws1.Cells(ws1.Rows.Count, ur1.Column).End(xlUp).Row > ur1.Row Then

            'Copy-paste visible data from Sheet1 to Sheet2
            .Offset(1).Resize(.Rows.Count - 1, .Columns.Count).Copy ws2.Cells(xRow2, 1)

            'Delete visible range with data from Sheet1
            .Offset(1).Resize(.Rows.Count - 1, .Columns.Count).EntireRow.Delete

        End If
        .AutoFilter
    End With
End Sub

这里textFileName =＆＃39; C：\ aRandomTextFile.txt＆＃39;。但是，如果我将它替换为类似于C：\ aRandomImage.png＆＃39;并替换

text = ''
textFile = open(textFileName, 'r', encoding='utf-8')
for textLine in textFile:
    text += textLine
textFile.close()   

ciphertext = text
numPassCounter = 0
for password in passwords:
    ciphertext = fEncode(ciphertext, password, num_passwords[numPassCounter])
    numPassCounter += 1       

os.system("copy /y " + textFileName + " " + ciphertextFileName)
ciphertextFile = open(ciphertextFileName, 'w', encoding='utf-8')
ciphertextFile.write(ciphertext)
ciphertextFile.close()

与

 ciphertextFile = open(textFileName, 'w', encoding='utf-8')

然后尝试

 ciphertextFile = open(textFileName, 'wb')

我得到了

 ciphertextFile.write(bytes(str(ciphertext, encoding='utf-8')))

我做错了什么？

Answer 1

问题在于你制作字节字符串的方式。请考虑以下内容，类似于您正在做的事情：

default_charset = "UTF-8"

或

>>> bytes('banana')
Traceback (most recent call last):
  File "<pyshell#0>", line 1, in <module>
    bytes('banana')
TypeError: string argument without an encoding

但现在尝试另一种方式：

>>> bytes(str('banana',encoding='utf-8'))
Traceback (most recent call last):
  File "<pyshell#1>", line 1, in <module>
    bytes(str('banana',encoding='utf-8'))
TypeError: decoding str is not supported

或

>>> bytes('banana'.encode('utf-8'))  # redundant, see last example
b'banana'

甚至只是：

>>> bytes(ord(c) for c in 'banana')
b'banana'

所以现在你可以看到>>> 'banana'.encode() b'banana'正在取一个字符串，使它成为二进制字符串，将其作为未编码的字符串，然后再尝试从中生成一个字节字符串。

希望有所帮助。

Answer 2

您是否尝试过var x = [2, 3, 8]; var sums = []; var sets = []; function SubSets(read, queued) { if( read.length == 4 || (read.length <= 4 && queued.length == 0) ) { if( read.length > 0 ){ var total = read.reduce(function(a,b){return a+b;},0); if(sums.indexOf(total)==-1){ sums.push(total); sets.push(read.slice().sort()); } } } else { SubSets(read.concat(queued[0]),queued.slice(1)); SubSets(read,queued.slice(1)); } } SubSets([],x); console.log(sums.sort(function(a,b){return a-b;}));

使用Python 3编写非文本文件

2 个答案: