Question

我只想尝试从android内部将位图上传到服务器。

我用Google搜索了一些内容并提出了这个问题，它实际上与另一个帖子完全相同，但它并不起作用。我不确定出了什么问题。从我的调试开始，当我做dos.flush（）时，我得到一个＆＃34; java.net.SocketException：sendto failed：EPIPE（Broken pipe）＆＃34;我不明白为什么。

这是我的安卓代码

class upload extends AsyncTask<Bitmap, Void, String>{
    @Override
    protected String doInBackground(Bitmap... params) {
        String attachmentName = "bitmap";
        String attachmentFileName = "bitmap.bmp";
        String crlf = "\r\n";
        String twoHyphens = "--";
        String boundary =  "*****";

        try {
            HttpURLConnection huc = null;
            URL url = new URL("http://dontenvy.me:5000/");
            huc = (HttpURLConnection) url.openConnection();


            huc.setChunkedStreamingMode(0);
            huc.setDoOutput(true);

            huc.setRequestMethod("POST");
            huc.setRequestProperty("Connection", "Keep-Alive");
            huc.setRequestProperty("Content-type", "multipart/form-data; boundary=" + boundary);

            DataOutputStream dos = new DataOutputStream(huc.getOutputStream());

            dos.writeBytes(twoHyphens + boundary + crlf);
            dos.writeBytes("Content-Disposition: form-data; name=\"" + attachmentName + "\"; filename=\"" + attachmentFileName + "\"" + crlf);
            dos.writeBytes(crlf);

            Bitmap small = Bitmap.createScaledBitmap(params[0], 100, 100, false);

            byte[] pixels = new byte[small.getWidth() * small.getHeight()];
            for (int i = 0; i < small.getWidth(); ++i) {
                for (int j = 0; j < small.getHeight(); ++j) {
                    //we're interested only in the MSB of the first byte,
                    //since the other 3 bytes are identical for B&W images
                    pixels[i + j] = (byte) ((small.getPixel(i, j) & 0x80) >> 7);
                }
            }

            dos.write(pixels);

            dos.writeBytes(crlf);

            dos.writeBytes(twoHyphens + boundary + twoHyphens + crlf);

            dos.flush();
            dos.close();
            huc.disconnect();

        }catch(MalformedURLException e){
            e.printStackTrace();
        }catch(IOException e){
            e.printStackTrace();
        }
        return null //once i get this working I'll do a response code return
    }


}

这是我的服务器端代码。我只是使用烧瓶，因为我觉得它最容易

import os
from flask import Flask, request, redirect, url_for
from werkzeug import secure_filename

UPLOAD_FOLDER = "/home/luisfmh/vigeo/uploads"
ALLOWED_EXTENSIONS = set(["png", "jpg", "bmp"])

app = Flask(__name__)

app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER

def allowed_file(filename):
    return '.' in filename and filename.rsplit(".", 1)[1] in ALLOWED_EXTENSIONS

@app.route("/", methods=["GET", "POST"])
def upload_file():

    print len(request.files)

    if request.method == "POST":
        file = request.files["bitmap"]
        if file: ##and allowed_file(file.filename):
            filename = secure_filename(file.filename)
            file.save(os.path.join(app.config["UPLOAD_FOLDER"], filename))
            return '''success!!'''
    return '''
    <!doctype html>
    <title> Upload new File</title>
    <h1> Upload new file</h1>
    <form action="" method=post enctype=multipart/form-data>
        <p><input type=file name=file>
            <input type=submit value=Upload>
    </form>
    '''

if __name__ == "__main__":
    app.run(debug=True, host = "0.0.0.0" )

android中的位图使用httpurlconnection发布到烧瓶网络服务器

0 个答案: