尝试在Hibernate中插入记录时获取SQLGrammarException

时间:2015-10-07 07:09:23

标签: java spring hibernate spring-mvc ms-access-2013

我收到以下异常 -
 org.hibernate.exception.SQLGrammarException:无法插入:[Employee]
以下是详细信息:

hibernate.cfg.xml中                  

    <hibernate-configuration>
    <session-factory>
    <property name="hibernate.dialect">org.hibernate.dialect.SQLServerDialect</property>
            <property name="hibernate.connection.driver_class">sun.jdbc.odbc.JdbcOdbcDriver</property>
            <property name="hibernate.connection.url">jdbc:odbc:Driver={Microsoft Access Driver (*.mdb, *.accdb)};DBQ=D:/Hibernate.accdb</property>
            <property name="connection.username"></property>
            <property name="connection.password"></property>
            <property name="connection.pool_size">1</property>
            <property name="current_session_context_class">thread</property>
            <property name="cache.provider_class">org.hibernate.cache.NoCacheProvider</property>
            <property name="show_sql">true</property>
            <property name="hbm2ddl.auto">update</property>
            <mapping resource="Employee.hbm.xml" />
    </session-factory>
    </hibernate-conf

Employee.hbm.xml           

<hibernate-mapping>
   <class name="Employee" table="EMPLOYEE">
      <meta attribute="class-description">
         This class contains the employee detail. 
      </meta>
      <id name="id" type="int" column="id">
         <generator class="native"/>
      </id>
      <property name="firstName" column="first_name" type="string"/>
      <property name="lastName" column="last_name" type="string"/>
      <property name="salary" column="salary" type="int"/>
   </class>
</hibernate-mapping>

Employee.java

public class Employee {
   private int id;
   private String firstName; 
   private String lastName;   
   private int salary;  

   public Employee() {}
   public Employee(String fname, String lname, int salary) {
      this.firstName = fname;
      this.lastName = lname;
      this.salary = salary;
   }
   public int getId() {
      return id;
   }
   public void setId( int id ) {
      this.id = id;
   }
   public String getFirstName() {
      return firstName;
   }
   public void setFirstName( String first_name ) {
      this.firstName = first_name;
   }
   public String getLastName() {
      return lastName;
   }
   public void setLastName( String last_name ) {
      this.lastName = last_name;
   }
   public int getSalary() {
      return salary;
   }
   public void setSalary( int salary ) {
      this.salary = salary;
   }
}

ManageEmployee.java

import java.util.List; 
import java.util.Date;
import java.util.Iterator; 

import org.hibernate.HibernateException; 
import org.hibernate.Session; 
import org.hibernate.Transaction;
import org.hibernate.SessionFactory;
import org.hibernate.cfg.Configuration;

public class ManageEmployee {
   private static SessionFactory factory; 
   public static void main(String[] args) {
      try{
         factory = new Configuration().configure().buildSessionFactory();
      }catch (Throwable ex) { 
         System.err.println("Failed to create sessionFactory object." + ex);
         throw new ExceptionInInitializerError(ex); 
      }
      ManageEmployee ME = new ManageEmployee();

      /* Add few employee records in database */
      Integer empID1 = ME.addEmployee("Zara", "Ali", 1000);
      Integer empID2 = ME.addEmployee("Daisy", "Das", 5000);
      Integer empID3 = ME.addEmployee("John", "Paul", 10000);
}
 public Integer addEmployee(String fname, String lname, int salary){
      Session session = factory.openSession();
      Transaction tx = null;
      Integer employeeID = null;
      try{
         tx = session.beginTransaction();
         Employee employee = new Employee(fname, lname, salary);
         employeeID = (Integer) session.save(employee); 
         tx.commit();
      }catch (HibernateException e) {
         if (tx!=null) tx.rollback();
         e.printStackTrace(); 
      }finally {
         session.close(); 
      }
      return employeeID;
   }

}

以下是完整的例外情况:

  

控制台输出:   Hibernate:插入EMPLOYEE(first_name,last_name,salary)值(?,?,?)select scope_identity()   org.hibernate.exception.SQLGrammarException:无法插入:[Employee]   Hibernate:插入EMPLOYEE(first_name,last_name,salary)值(?,?,?)select scope_identity()       在org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:92)       在org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:66)       在org.hibernate.id.insert.AbstractReturningDelegate.performInsert(AbstractReturningDelegate.java:64)       在org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2327)       在org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2834)       在org.hibernate.action.EntityIdentityInsertAction.execute(EntityIdentityInsertAction.java:71)       在org.hibernate.engine.ActionQueue.execute(ActionQueue.java:273)       at org.hibernate.event.def.AbstractSaveEventListener.performSaveOrReplicate(AbstractSaveEventListener.java:320)       在org.hibernate.event.def.AbstractSaveEventListener.performSave(AbstractSaveEventListener.java:203)       at org.hibernate.event.def.AbstractSaveEventListener.saveWithGeneratedId(AbstractSaveEventListener.java:129)       at org.hibernate.event.def.DefaultSaveOrUpdateEventListener.saveWithGeneratedOrRequestedId(DefaultSaveOrUpdateEventListener.java:210)       at org.hibernate.event.def.DefaultSaveEventListener.saveWithGeneratedOrRequestedId(DefaultSaveEventListener.java:56)       在org.hibernate.event.def.DefaultSaveOrUpdateEventListener.entityIsTransient(DefaultSaveOrUpdateEventListener.java:195)       在org.hibernate.event.def.DefaultSaveEventListener.performSaveOrUpdate(DefaultSaveEventListener.java:50)       在org.hibernate.event.def.DefaultSaveOrUpdateEventListener.onSaveOrUpdate(DefaultSaveOrUpdateEventListener.java:93)       在org.hibernate.impl.SessionImpl.fireSave(SessionImpl.java:713)       在org.hibernate.impl.SessionImpl.save(SessionImpl.java:701)       在org.hibernate.impl.SessionImpl.save(SessionImpl.java:697)       在ManageEmployee.addEmployee(ManageEmployee.java:47)       在ManageEmployee.main(ManageEmployee.java:23)   引起:java.sql.SQLException:[Microsoft] [ODBC Microsoft Access驱动程序]在SQL语句结束时缺少分号(;)。       at sun.jdbc.odbc.JdbcOdbc.createSQLException(Unknown Source)       at sun.jdbc.odbc.JdbcOdbc.standardError(Unknown Source)       at sun.jdbc.odbc.JdbcOdbc.SQLExecute(Unknown Source)       at sun.jdbc.odbc.JdbcOdbcPreparedStatement.execute(Unknown Source)       at org.hibernate.id.IdentityGenerator $ InsertSelectDelegate.executeAndExtract(IdentityGenerator.java:138)       at org.hibernate.id.insert.AbstractReturningDelegate.performInsert(AbstractReturningDelegate.java:57)       ......还有17个   org.hibernate.exception.SQLGrammarException:无法插入:[Employee]       在org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:92)       在org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:66)       在org.hibernate.id.insert.AbstractReturningDelegate.performInsert(AbstractReturningDelegate.java:64)       在org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2327)       在org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2834)       在org.hibernate.action.EntityIdentityInsertAction.execute(EntityIdentityInsertAction.java:71)       在org.hibernate.engine.ActionQueue.execute(ActionQueue.java:273)       at org.hibernate.event.def.AbstractSaveEventListener.performSaveOrReplicate(AbstractSaveEventListener.java:320)       在org.hibernate.event.def.AbstractSaveEventListener.performSave(AbstractSaveEventListener.java:203)       at org.hibernate.event.def.AbstractSaveEventListener.saveWithGeneratedId(AbstractSaveEventListener.java:129)       at org.hibernate.event.def.DefaultSaveOrUpdateEventListener.saveWithGeneratedOrRequestedId(DefaultSaveOrUpdateEventListener.java:210)       at org.hibernate.event.def.DefaultSaveEventListener.saveWithGeneratedOrRequestedId(DefaultSaveEventListener.java:56)       在org.hibernate.event.def.DefaultSaveOrUpdateEventListener.entityIsTransient(DefaultSaveOrUpdateEventListener.java:195)       在org.hibernate.event.def.DefaultSaveEventListener.performSaveOrUpdate(DefaultSaveEventListener.java:50)       在org.hibernate.event.def.DefaultSaveOrUpdateEventListener.onSaveOrUpdate(DefaultSaveOrUpdateEventListener.java:93)       在org.hibernate.impl.SessionImpl.fireSave(SessionImpl.java:713)       在org.hibernate.impl.SessionImpl.save(SessionImpl.java:701)       在org.hibernate.impl.SessionImpl.save(SessionImpl.java:697)       在ManageEmployee.addEmployee(ManageEmployee.java:47)       在ManageEmployee.main(ManageEmployee.java:24)   引起:java.sql.SQLException:[Microsoft] [ODBC Microsoft Access驱动程序]在SQL语句结束时缺少分号(;)。       at sun.jdbc.odbc.JdbcOdbc.createSQLException(Unknown Source)       at sun.jdbc.odbc.JdbcOdbc.standardError(Unknown Source)       at sun.jdbc.odbc.JdbcOdbc.SQLExecute(Unknown Source)       at sun.jdbc.odbc.JdbcOdbcPreparedStatement.execute(Unknown Source)       at org.hibernate.id.IdentityGenerator $ InsertSelectDelegate.executeAndExtract(IdentityGenerator.java:138)       at org.hibernate.id.insert.AbstractReturningDelegate.performInsert(AbstractReturningDelegate.java:57)       ......还有17个   org.hibernate.exception.SQLGrammarException:无法插入:[Employee]       在org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:92)       在org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:66)       在org.hibernate.id.insert.AbstractReturningDelegate.performInsert(AbstractReturningDelegate.java:64)       在org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2327)       在org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:2834)       在org.hibernate.action.EntityIdentityInsertAction.execute(EntityIdentityInsertAction.java:71)       在org.hibernate.engine.ActionQueue.execute(ActionQueue.java:273)       at org.hibernate.event.def.AbstractSaveEventListener.performSaveOrReplicate(AbstractSaveEventListener.java:320)       在org.hibernate.event.def.AbstractSaveEventListener.performSave(AbstractSaveEventListener.java:203)       at org.hibernate.event.def.AbstractSaveEventListener.saveWithGeneratedId(AbstractSaveEventListener.java:129)       at org.hibernate.event.def.DefaultSaveOrUpdateEventListener.saveWithGeneratedOrRequestedId(DefaultSaveOrUpdateEventListener.java:210)       at org.hibernate.event.def.DefaultSaveEventListener.saveWithGeneratedOrRequestedId(DefaultSaveEventListener.java:56)       在org.hibernate.event.def.DefaultSaveOrUpdateEventListener.entityIsTransient(DefaultSaveOrUpdateEventListener.java:195)       在org.hibernate.event.def.DefaultSaveEventListener.performSaveOrUpdate(DefaultSaveEventListener.java:50)       在org.hibernate.event.def.DefaultSaveOrUpdateEventListener.onSaveOrUpdate(DefaultSaveOrUpdateEventListener.java:93)       在org.hibernate.impl.SessionImpl.fireSave(SessionImpl.java:713)       在org.hibernate.impl.SessionImpl.save(SessionImpl.java:701)       在org.hibernate.impl.SessionImpl.save(SessionImpl.java:697)       在ManageEmployee.addEmployee(ManageEmployee.java:47)       在ManageEmployee.main(ManageEmployee.java:25)   引起:java.sql.SQLException:[Microsoft] [ODBC Microsoft Access驱动程序]在SQL语句结束时缺少分号(;)。       at sun.jdbc.odbc.JdbcOdbc.createSQLException(Unknown Source)       at sun.jdbc.odbc.JdbcOdbc.standardError(Unknown Source)       at sun.jdbc.odbc.JdbcOdbc.SQLExecute(Unknown Source)       at sun.jdbc.odbc.JdbcOdbcPreparedStatement.execute(Unknown Source)       at org.hibernate.id.IdentityGenerator $ InsertSelectDelegate.executeAndExtract(IdentityGenerator.java:138)       at org.hibernate.id.insert.AbstractReturningDelegate.performInsert(AbstractReturningDelegate.java:57)       ......还有17个   Hibernate:插入EMPLOYEE(first_name,last_name,salary)值(?,?,?)select scope_identity()

请帮助解决例外情况。 提前谢谢!

1 个答案:

答案 0 :(得分:0)

Hibernate库中不存在MS Access方言。这导致Hibernate无法检测身份列,并且无法满足MS Access的需要。

  

org.hibernate.exception.SQLGrammarException:无法插入:[Employee] Hibernate:插入EMPLOYEE(first_name,last_name,salary)值(?,?,?) select scope_identity() < / p>

select scope_identity()是MS Access不支持的TRANSACT-SQL实例。

您可以执行以下选项之一:

  • 请勿使用自动生成的id列或不使用SQL标准字段。
  • 使用受支持的MS Access Hibernate doc创建的hibernate数据库。
  • 创建您自己的hibernate方言以支持MS Access或使用thirdparty one提供MS Access的特殊功能。

How can I use hibernate with MS Access?

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