我有以下情节:
我希望将线性趋势线拟合到数据中,因此我可以在进一步计算中使用斜率。但是,当我尝试拟合线性趋势线时,我得到了这个:
如果我适合功率趋势线,那么我得到的R ^ 2超过.999,但这条趋势线对我来说没用......有没有人知道实现这个的正确方法?
编辑:以下是CSV格式的数据
Iron in Copper,,,Cobalt in Copper,,,Nickel in Copper,,
T (oC),D (cm2/sec),1/T (1/K),T (oC),D (cm2/sec),1/T (1/K),T (oC),D (cm2/sec),1/T (1/K)
1074,5.65E-09,0.0007423078,1077,3.43E-09,0.0007406584,1076,1.98E-09,0.0007412074
974,1.11E-09,0.0008018282,983,7.64E-10,0.0007960833,980,3.57E-10,0.0007979891
895,2.86E-09,0.0008560544,904,1.77E-10,0.0008495094,900,7.87E-11,0.0008524059
830,7.80E-11,0.000906495,844,5.09E-11,0.0008951349,847,2.61E-11,0.0008927376
780,2.67E-11,0.0009495324,793,1.65E-11,0.0009379543,791,6.82E-12,0.0009397171
719,6.55E-12,0.0010079121,744,5.31E-12,0.0009831392,743,1.90E-12,0.0009841067
,,,701,1.76E-12,0.001026536,,,