Question

我是Google Script的新手，并决定尝试位于底部的文档代码。代码位于：

function createAndSendDocument() {
   // Create a new Google Doc named 'Hello, world!'
   var doc = DocumentApp.create('Hello, world!');

   // Access the body of the document, then add a paragraph.
   doc.getBody().appendParagraph('This document was created by Google Apps Script.');

   // Get the URL of the document.
   var url = doc.getUrl();

   // Get the email address of the active user - that's you.
   var email = Session.getActiveUser().getEmail();

   // Get the name of the document to use as an email subject line.
   var subject = doc.getName();

   // Append a new string to the "url" variable to use as an email body.
   var body = 'Link to your doc: ' + url;

   // Send yourself an email with a link to the document.
   GmailApp.sendEmail(email, subject, body);
}

代码工作得很好，但由于每次运行时都不希望它创建新文档，我将代码编辑为：

function sendDocument() {
   // Get the name of the document to use as an email subject line.
   var doc = DocumentApp.getActiveDocument();

   // Get the email address of the active user - that's you.
   var email = Session.getActiveUser().getEmail();

   // Append a new string to use as an email body.
   var body = 'Link to your doc: ' + doc.getUrl() + '. Happy editing! :D';

   // Send yourself an email with a link to the document.
   GmailApp.sendEmail(email, doc, body);
}

但是，我无法运行上面的代码并弹出一条错误消息：

TypeError: Cannot call method "getUrl" of null. (line 9, file "")

这是我的执行记录：

[15-10-03 10:13:26:875 PDT] Starting execution
[15-10-03 10:13:26:881 PDT] DocumentApp.getActiveDocument() [0 seconds]
[15-10-03 10:13:26:883 PDT] Session.getActiveUser() [0 seconds]
[15-10-03 10:13:26:883 PDT] User.getEmail() [0 seconds]
[15-10-03 10:13:26:886 PDT] Execution failed: TypeError: Cannot call method "getUrl" of null. (line 9, file "Code") [0.003 seconds total runtime]

任何人都可以帮我解决这个问题吗？提前致谢！：）

Answer 1

使用document.getActiveDocument（）。该脚本必须是容器绑定的。因此脚本必须与文档相关联。您可以从文档的工具＆gt;脚本编辑器中打开它。

如果您只是创建一个新的脚本项目，它将找不到“活动文档”。

编辑：即使脚本代码与Document关联，它也不适用于使用doGet的Web发布的应用程序。您必须首先使用诸如... openById（''）

之类的方法获取文档

为什么这个代码不能使用.getUrl？

1 个答案: