Question

如何仅在两个定义的顶点之间的某些边上应用AllShortestPaths（）？

以下是查询：

MATCH
    (from: SHIPPING_NODE {...}),
    (to: SHIPPING_NODE {...}), 
    paths = allShortestPaths((from)-[connection:CONNECT*]->(to))
WITH
    ....
RETURN delay_min, delay_max, price, route

当我向查询添加WHERE connection.field_value > 10时，我得到以下内容：

Type mismatch: expected Map, Node or Relationship but was Collection<Relationship> (line 5, column 7 (offset: 267))
"WHERE connection.field_value > 10"
connection has some fields that I need to select specifically

注意：我可以通过从allShortestPaths((from)-[connection:CONNECT*]->(to))删除星号（*）来清除错误，但不再返回任何内容

Answer 1

如果路径包含多个关系，您将获得一系列关系。

您可以指定所有连接关系的字段值应大于10：

WHERE ALL(x IN rels(paths) WHERE x.field_value > 10)

参考：http://neo4j.com/docs/stable/query-predicates.html#functions-all

如何仅在两个定义的顶点之间的某些边上应用AllShortestPaths（）？

1 个答案: