Question

我收到以下错误：

Warning: mysqli_stmt::bind_param(): Number of variables doesn't match number of parameters in prepared statement

我无法绑定并执行prepare语句。已成功建立与数据库的连接，并确实将其插入到数据库中，初始值为?

以下是代码：

// Set up the query
$insert = "INSERT INTO record_user (ip,country,address,stack,skills,employment_type,city_selection,landing_time,submission_time,time_spent) 
VALUES ('?','?','?','?','?','?','?','?','?','?')";


// Prepare the statement
$insert = $con->prepare($insert);

// Bind the statement
$insert->bind_param("ssssssssss", $user_ip, $country, $location, $stack, $skills, $employment, $city, $landing_time, $submission_time, $time_spent);

// Execute the statement
$insert->execute();

// Close the statement connection
$insert->close();

// Close the database connection
$con->close();

Answer 1

丢失?周围的引号并使用10个参数而不是11个

而不是：

$insert = "INSERT INTO record_user (ip,country,address,stack,skills,employment_type,city_selection,landing_time,submission_time,time_spent) 
VALUES ('?','?','?','?','?','?','?','?','?','?')";
$insert = $con->prepare($insert);
$insert->bind_param("ssssssssss", $user_ip, $country, $location, $stack, $skills, $employment, $city, $landing_time, $submission_time, $time_spent);

试试这个：

$insert = "INSERT INTO record_user (ip,country,address,stack,skills,employment_type,city_selection,landing_time,submission_time,time_spent)
VALUES (?,?,?,?,?,?,?,?,?,?)";
$insert = $con->prepare($insert);
$insert->bind_param("ssssssssss", $user_ip, $country, $location, $stack, $skills, $employment, $city, $landing_time, $submission_time, $time_spent);

Answer 2

您准备好的查询没有任何占位符。您正在向数据库中插入10个文字 ?个字符。

您需要丢失? s周围的引号：

$insert = "INSERT INTO record_user (ip,country,address,stack,skills,employment_type,city_selection,landing_time,submission_time,time_spent)
    VALUES (?,?,?,?,?,?,?,?,?,?)";

警告：mysqli_stmt :: bind_param（）：变量数与预准备语句中的参数数量不匹配

2 个答案: