Question

我构建了这段代码，我想做多搜索。

从表格搜索：商品，商店，类别。

但是，当我在查询之间建立联盟时，我无法进行链接。

类别需要category.php?id=1
项目需要item.php?id=1
商店需要store.php?id=1

但是当我结合时，我得到了这个：

id | name 
----------
1 | google
2 | love 
3 | shop 

$query = '(SELECT id,name FROM `item` WHERE `accepted` = '1' AND `name` LIKE '%".$search."%')
           UNION ALL
           (SELECT id,name FROM `category` WHERE `name` LIKE '%".$search."%')
           UNION ALL
           (SELECT id,name FROM `store` WHERE `accepted` = '1' AND `name` LIKE '%".$search."%')
           LIMIT 25
';

我怎么知道哪个表格能得到这些信息呢？
谢谢！

Answer 1

将表添加到子查询中：

(SELECT id, name, 'item' as which FROM `item` WHERE `accepted` = '1' AND `name` LIKE '%".$search."%')
UNION ALL
(SELECT id, name, 'category' as which FROM `category` WHERE `name` LIKE '%".$search."%')
UNION ALL
(SELECT id, name, 'store' as which FROM `store` WHERE `accepted` = '1' AND `name` LIKE '%".$search."%');
LIMIT 25

Answer 2

只需添加一个包含源名称的虚拟列：

$query = '(SELECT "item" as table, id,name FROM `item` WHERE `accepted` = '1' AND `name` LIKE '%".$search."%')
           UNION ALL
           (SELECT "category" AS table, id,name FROM `category` WHERE `name` LIKE '%".$search."%')
           UNION ALL
           (SELECT "store" AS table, id,name FROM `store` WHERE `accepted` = '1' AND `name` LIKE '%".$search."%')
           LIMIT 25
';

Answer 3

将其作为值添加到您的查询中：

$query = "(SELECT id,name,'item' FROM `item` WHERE `accepted` = '1' AND `name` LIKE '%".$search."%')
           UNION ALL
           (SELECT id,name,'CATEGORY' FROM `category` WHERE `name` LIKE '%".$search."%')
           UNION ALL
           (SELECT id,name,'STORE' FROM `store` WHERE `accepted` = '1' AND `name` LIKE '%".$search."%')
           LIMIT 25";

所以你会知道记录的来源

我怎么知道从查询中获得哪个表？

3 个答案: