Question

当我尝试存储blob（通过XMLHttpRequest GET请求检索时，iOS 8.4上的Safari会抛出错误：

DataCloneError: DOM IDBDatabase Exception 25: The data being stored could
not be cloned by the internal structured cloning algorithm

我的代码以及此示例也发生了这种情况：http://robnyman.github.io/html5demos/indexeddb/

这是导致我的代码（以及上面的示例）失败的行：

//This throws the error
var put = transaction.objectStore("elephants").put(blob, "image");

有解决方法吗？ blob是否需要首先进行base64编码（就像你必须使用WebSQL一样）？

我的代码 （适用于Android版桌面Chrome / Firefox和Chrome / Firefox）：

var xhr = new XMLHttpRequest();
var blob;

//Get the Video
xhr.open( "GET", "test.mp4", true );

//Set as blob
xhr.responseType = "blob";

//Listen for blob
xhr.addEventListener("load", function () {
        if (xhr.status === 200) {
            blob = xhr.response;

            //Start transaction
            var transaction = db.transaction(["Videos"], "readwrite");

            //IT FAILS HERE
            var put = transaction.objectStore("Videos").put(blob, "savedvideo");

        }
        else {
            console.log("ERROR: Unable to download video." );
        }
}, false);

xhr.send();

Answer 1

对于某些奇怪的原因（它是一个bug），就像iOS Safari 7的WebSQL一样，无法在iOS上的IndexedDB中存储BLOB Safari 8.您必须将其转换为base64，然后它将存储没有错误。（我再说一遍，这是一个错误）

因此，请将代码更改为：

更改回复类型

xhr.responseType = "arraybuffer";

从XMLHttpRequest检索后存储在数据库中

//We'll make an array of unsigned ints to convert
var uInt8Array = new Uint8Array(xhr.response);
var i = uInt8Array.length;
var binaryString = new Array(i);
while (i--)
{
    //Convert each to character
    binaryString[i] = String.fromCharCode(uInt8Array[i]);
}

//Make into a string
var data = binaryString.join('');

//Use built in btoa to make it a base64 encoded string
var base64 = window.btoa(data);

//Now we can save it
var transaction = db.transaction(["Videos"], "readwrite");
var put = transaction.objectStore("Videos").put(base64, "savedvideo");

从IndexedDB中检索表单后，将其转换回来：

//Convert back to bytes
var data = atob( event.target.result );

//Make back into unsigned array
var asArray = new Uint8Array(data.length);

for( var i = 0, len = data.length; i < len; ++i ) 
{
    //Get back as int
    asArray[i] = data.charCodeAt(i);    
}

//Make into a blob of proper type
var blob = new Blob( [ asArray.buffer ], {type: "video/mp4"} );

//Make into object url for video source
var videoURL = URL.createObjectURL(blob);

尝试在iOS Safari 8中存储blob会引发DataCloneError

1 个答案: