我有以下2个功能可以在谷歌地图中提取,地理编码和放置标记。
我不断得到TypeError: adds[i] is undefined
,这当然会导致地图的其余部分爆炸。
这是我的代码:
// Place Markers on the Map
var PlaceMarkers = function (iw, adds, gc) {
var image = {url: "http://meatmysite.com/Images/star2.png", size: new google.maps.Size(24, 24)};
var aCt = adds.length;
for(var i = 0; i < aCt; ++i) {
GetLatLng(gc, adds[i].address, function(pos) {
if(pos) {
var ipop = '<h1>' + adds[i].title + '</h1>'; // <----- TypeError: adds[i] is undefined
if(!isBlank(adds[i].url)){
ipop += '<a href="' + adds[i].url + '" target="_blank">' + adds[i].url + '</a><br />';
}
ipop += '<div class="map_item_content" id="mi_content' + i + '">' + adds[i].content + '</div>';
if(!isBlank(adds[i].mainphone)){
ipop += '<br /><strong>Phone:</strong> <a href="tel:'+adds[i].mainphone+'">' + adds[i].mainphone + '</a>';
}
if(!isBlank(adds[i].mainemail)){
ipop += '<br /><strong>Email:</strong> <a href="mailto:'+adds[i].mainemail+'">' + adds[i].mainemail + '</a>';
}
console.log('HEY NOW: ' + pos.toString() + ' - Location Found!');
var mark = new google.maps.Marker({title: adds[i].title, position: pos, map: map, icon: image, html: ipop});
google.maps.event.addListener(mark, 'click', function(){
iw.setContent(this.html);
iw.open(map, this);
});
}
});
}
};
// Get Lat/Lng Location
var GetLatLng = function(gc, add, f) {
var ret = '';
gc.geocode({'address': add}, function(res, status) {
if (status == 'OK') {
f(res[0].geometry.location);
console.log('Found Here: ' + ret.toString());
}
});
return -1;
};
DEMO返回数据添加
[
{
"address": "1 My Street Gilbert, AZ 85234",
"title": "My Title 1",
"url": "http://www.myurl.com/",
"mainphone": null,
"mainemail": null,
"content": "1 My Street<br />Gilbert, AZ 85234"
},
{
"address": "2 My Street North Richland Hills, TX 76182",
"title": "My Title 2",
"url": null,
"mainphone": null,
"mainemail": null,
"content": "2 My Street<br />North Richland Hills, TX 76182"
}
]
答案 0 :(得分:1)
一个选项,将完整的“地址”对象传递给GetLatLng
函数,并从那里传递回其回调(因此你可以获得函数闭包):
// Get Lat/Lng Location
var GetLatLng = function (gc, add, f) {
gc.geocode({
'address': add.address
}, function (res, status) {
if (status == 'OK') {
f(res[0].geometry.location, add);
}
});
};
然后在回调中使用它(你也可以只将索引传递给数组):
GetLatLng(gc, adds[i], function (pos, add) {
if (pos) {
var ipop = '<h1>' + add.title + '</h1>';
if (!isBlank(add.url)) {
ipop += '<a href="' + add.url + '" target="_blank">' + add.url + '</a><br />';
}
ipop += '<div class="map_item_content" id="mi_content' + i + '">' + add.content + '</div>';
if (!isBlank(add.mainphone)) {
ipop += '<br /><strong>Phone:</strong> <a href="tel:' + add.mainphone + '">' + add.mainphone + '</a>';
}
if (!isBlank(add.mainemail)) {
ipop += '<br /><strong>Email:</strong> <a href="mailto:' + add.mainemail + '">' + add.mainemail + '</a>';
}
console.log('HEY NOW: ' + pos.toString() + ' - Location Found!');
var mark = new google.maps.Marker({
title: add.title,
position: pos,
map: map,
icon: image,
html: ipop
});
google.maps.event.addListener(mark, 'click', function () {
iw.setContent(this.html);
iw.open(map, this);
});
}
});
代码段
var geocoder = new google.maps.Geocoder();
var map;
var infoWindow = new google.maps.InfoWindow();
function initialize() {
map = new google.maps.Map(
document.getElementById("map_canvas"), {
center: new google.maps.LatLng(37.4419, -122.1419),
zoom: 13,
mapTypeId: google.maps.MapTypeId.ROADMAP
});
PlaceMarkers(infoWindow, adds, geocoder);
}
google.maps.event.addDomListener(window, "load", initialize);
// Place Markers on the Map
var PlaceMarkers = function(iw, adds, gc) {
var bounds = new google.maps.LatLngBounds();
var image = {
url: "http://meatmysite.com/Images/star2.png",
size: new google.maps.Size(24, 24)
};
var aCt = adds.length;
for (var i = 0; i < aCt; ++i) {
GetLatLng(gc, adds[i], function(pos, add) {
if (pos) {
var ipop = '<h1>' + add.title + '</h1>'; // <----- TypeError: adds[i] is undefined
if (!isBlank(add.url)) {
ipop += '<a href="' + add.url + '" target="_blank">' + add.url + '</a><br />';
}
ipop += '<div class="map_item_content" id="mi_content' + i + '">' + add.content + '</div>';
if (!isBlank(add.mainphone)) {
ipop += '<br /><strong>Phone:</strong> <a href="tel:' + add.mainphone + '">' + add.mainphone + '</a>';
}
if (!isBlank(add.mainemail)) {
ipop += '<br /><strong>Email:</strong> <a href="mailto:' + add.mainemail + '">' + add.mainemail + '</a>';
}
console.log('HEY NOW: ' + pos.toString() + ' - Location Found!');
var mark = new google.maps.Marker({
title: add.title,
position: pos,
map: map,
// icon: image,
html: ipop
});
bounds.extend(mark.getPosition());
map.fitBounds(bounds);
google.maps.event.addListener(mark, 'click', function() {
iw.setContent(this.html);
iw.open(map, this);
});
}
});
}
};
// Get Lat/Lng Location
var GetLatLng = function(gc, add, f) {
gc.geocode({
'address': add.address
}, function(res, status) {
if (status == 'OK') {
f(res[0].geometry.location, add);
}
});
};
var adds = [{
"address": "1 My Street Gilbert, AZ 85234",
"title": "My Title 1",
"url": "http://www.myurl.com/",
"mainphone": null,
"mainemail": null,
"content": "1 My Street<br />Gilbert, AZ 85234"
}, {
"address": "2 My Street North Richland Hills, TX 76182",
"title": "My Title 2",
"url": null,
"mainphone": null,
"mainemail": null,
"content": "2 My Street<br />North Richland Hills, TX 76182"
}];
function isBlank(str) {
return (!str || /^\s*$/.test(str));
}
html,
body,
#map_canvas {
height: 100%;
width: 100%;
margin: 0px;
padding: 0px
}
<script src="https://maps.googleapis.com/maps/api/js"></script>
<div id="map_canvas"></div>
答案 1 :(得分:0)
这看起来像是典型的绑定问题。当您的回调被调用时,adds[i]
的值将发生变化。循环很可能终止,i
现在的值为last index + 1
,这表示什么都没有。请注意,它也可能指向错误的索引,该索引不会失败但使用错误的数据。
您必须在本地为每次迭代绑定adds[i]
的值,否则回调将仅使用对全局值的引用。有多种方法可以解决这个问题,这里有一个简单的方法,我们不断将adds[i]
作为函数参数传递。
在调用adds[i].address
时将adds[i]
替换为GetLatLng
,并在回调中添加第二个参数add
:
GetLatLng(gc, adds[i], function(pos, add) {
...
});
然后修改GetLatLng
以使用add.address
而不只是add
并将add
添加到回调调用中:
// Get Lat/Lng Location
var GetLatLng = function(gc, add, f) {
var ret = '';
gc.geocode({'address': add.address}, function(res, status) {
if (status == 'OK') {
f(res[0].geometry.location, add);
console.log('Found Here: ' + ret.toString());
}
});
return -1;
};
然后在回调函数中,将adds[i]
的所有实例替换为add
以使用局部变量。
我没有设置测试但理论上应该可行。
答案 2 :(得分:0)
String url = Html.fromHtml("http://sexocomcafe1-teste.tempsite.ws/imagensUsuario13/avata/Atra%C3%A7%C3%A3o%20PerigosaRJ_44690132.jpg").toString();
Picasso.with(this)
.load(url)
.into(img);
答案 3 :(得分:-1)
for(var i = 0; i < aCt - 1; ++i)
。您需要在for循环中添加“-1”。数组从索引0开始而不是1.您还需要小心使用for循环中的函数。在javascript中,for循环没有自己的范围。只有函数才能创建新的范围。