我在一个网站的职业页面上有2个iframe,客户端已经向我提供了iframe,他们的开放位置来自iframe。我已将其设置为当您点击链接或图像时,iframe通过.toggle()打开和关闭; 这是我的代码:
<div class="OpenPositions-left">
<div class="position-city">
<h2><a href="<?php the_field('view_positions_link_left'); ?>" class="ny-positions"><?php the_field('position_city_left'); ?></a></h2>
</div>
<a href="<?php the_field('view_positions_link_left'); ?>" class="ny-positions">
<img src="<?php the_field('open_positions_left'); ?>" />
</a>
<a href="<?php the_field('view_positions_link_left'); ?>" class="ny-positions"><?php the_field('view_positions_left'); ?></a>
</div><!-- end of open positions left -->
<div class="OpenPositions-right">
<div class="position-cityRight">
<h2><a href="<?php the_field('view_positions_link_right'); ?>" class="rus-positions"><?php the_field('position_city_right'); ?></a></h2>
</div>
<a href="<?php the_field('view_positions_link_right'); ?>" class="rus-positions">
<img src="<?php the_field('open_positions_right'); ?>" />
</a>
<a href="<?php the_field('view_positions_link_right'); ?>" class="rus-positions"><?php the_field('view_positions_right'); ?></a>
<script type="text/javascript" src=""></script>
<div id="iframeHeightDiv" name="" align="center" class="newyork-iframe openjobs-container">
<iframe id="inlineframe" name=""src="" frameborder="0" allowtransparency="true" sandbox="allow-forms allow-scripts allow-same-origin"> </iframe>
</div><!-- end of iframe -->
<div id="hr" class="rushr openjobs-container">
<script src="second-ifrmae.php"></script>
</div><!-- end of bamboohr -->
</div><!-- end of OpenPositions -->
<script>
jQuery(document).ready(function($) {
$('div.openjobs-container').each(function() {
var $OpenJobs = $(this);
$('openjobs-container', $OpenJobs).click(function(e) {
e.preventDefault();
$div = $(div.'openjobs-container').not($div).hide();
return false;
});
});
});
</script>
代码没有提出任何建议?
答案 0 :(得分:0)
您在此代码块中遇到问题:
$sql = "SELECT * FROM members ORDER BY name"; // Database query and results
$result = mysqli_query($connection, $sql);
if ( $result == false )
{
// handle error with mysqli_... functions
}
else
{
while($row = mysqli_fetch_array($result)) {
...
这行代码中的选择器:
$('openjobs-container', $OpenJobs).click(function(e) {
e.preventDefault();
$div = $(div.'openjobs-container').not($div).hide();
return false;
});
应该是一个字符串:
$div = $(div.'openjobs-container').not($div).hide();