Question

我在Oracle MCS中创建了一个自定义API以获取用户信息并尝试从MAF应用程序调用它...作为响应，我获得200作为成功代码...但是当我尝试解析响应时显示HTML页面而不是实际响应....

自定义API

https://mobileportalsetrial1304dev-mcsdem0001.mobileenv.us2.oraclecloud.com:443/mobile/custom/rvs_ekkfetchuserinfo/fetchcontent 和userid=101作为参数

调用方法获取用户信息

    @Override
public Response getUserInformation(int userId) {
    System.out.println("In loginService");
    String restURI = "https://mobileportalsetrial1304dev-mcsdem0001.mobileenv.us2.oraclecloud.com:443/mobile/custom/rvs_ekkfetchuserinfo/fetchcontent?userid=" + userId;
    String jsonRequest = "";

    Response response = new Response();

    response = RestUtil.callGet(restURI, jsonRequest);

    return response;
}

callGet方法

public static Response callGet(String restURI, String jsonRequest) {
    String responseJson = "";
    Response response = new Response();
    System.out.println("restURI:" + restURI);

    RestServiceAdapter restServiceAdapter = Model.createRestServiceAdapter();
    restServiceAdapter.clearRequestProperties();
    restServiceAdapter.setConnectionName("MiddlewareAPI");
    restServiceAdapter.setRequestType(RestServiceAdapter.REQUEST_TYPE_GET);

    restServiceAdapter.addRequestProperty("Content-Type", "application/json");
    restServiceAdapter.addRequestProperty("Accept", "application/json; charset=UTF-8");
    restServiceAdapter.addRequestProperty("Oracle-Mobile-Backend-Id", "da5c7d86-29c0-43e8-b613-53de55a7ae6c");
    restServiceAdapter.addRequestProperty("Authorization", "Basic TUNTREVNMDAwMV9NT0JJTEVQT1JUQUxTRVRSSUFMMTMwNERFVl9NT0JJTEVfQU5PTllNT1VTX0FQUElEOmR5Nm91NW5wX3RnbE5r");//+new String(encodedBytes));

    restServiceAdapter.setRequestURI(restURI);
    restServiceAdapter.setRetryLimit(0);

    try {
        responseJson = restServiceAdapter.send(jsonRequest);
        System.out.println("response" + responseJson);
        int responseCode = restServiceAdapter.getResponseStatus();
        System.out.println("responseCode" + responseCode);
        response.setResponseCode(responseCode);
        response.setResponseMessage(responseJson);
        response.setHeader(restServiceAdapter.getResponseHeaders());
    } catch (Exception e) {
        System.out.println("Error in calling API" + e.getStackTrace());

        int responseCode = restServiceAdapter.getResponseStatus();
        response.setResponseCode(responseCode);
        response.setResponseMessage(responseJson);

    }


    return response;
}

Json Parsing

JSONObject obj = new JSONObject(response);
JSONArray arr = obj.getJSONArray("posts");
for (int i = 0; i < arr.length(); i++)
{
    String user_id = arr.getJSONObject(i).getString("UserId");
}

这里我得到的是找不到JSONObject [“items”] ...当我打印出响应消息时，它会提供一个HTML脚本文件

预期产出

{
    "items": [
        {
            "UserId": "101",
            "AgentId": null,
            "Category": "Rental",
            "Division": "KDR",
            "Status": null,
            "LocationId": null,
            "Operation": "CheckOut",
            "Admin": "N",
            "createdBy": "mcs-demo_user09@oracleads.com",
            "createdOn": "2015-09-25T11:29:10.215564+00:00",
            "modifiedBy": "mcs-demo_user09@oracleads.com",
            "modifiedOn": "2015-09-25T11:29:10.215564+00:00"
        }
    ]
}

Answer 1

HTML页面的内容是什么（我会假设它有一些JavaScript，但也应该有HTML标题）。无论如何，MCS中的用户ID不是101而是内部ID，因此我不知道您是否在此问题中选择了101以进行简化。

在MAF中，REST连接是通过与根URL和相对URI的REST连接定义的。在您的示例中，REST连接被引用为“MiddlewareAPI”。除非此连接的值为null，否则您提供的restURI需要减少为不包含根URL。

您获得的HTTP 200，因为服务器回答了请求。但是，它似乎缺少授权用户（如果访问API的基本授权失败）或者不允许经过身份验证的用户请求用户平台API（默认情况下，您只能请求有关用户的信息）认证为）。

谢

Answer 2

嗨，我得到了解决方案...... 我试图通过Oracle-MCS调用customAPI。我将RestServiceAdapter替换为HttpsURLConnection。然后它完美无缺。

来自MAF应用程序的Oracle MCS Custom API调用

自定义API

调用方法获取用户信息

callGet方法

Json Parsing

预期产出

2 个答案: