Question

我正在尝试使用php验证制作一个html表单，但尝试提交至少有一个填充文本字段的表单会说电子邮件不匹配（自制的部分代码不应该显示。

    <?php
error_reporting(0);


if(isset($_POST["submit"])){
  //File Verification

if(empty($_POST['username']) && empty($_POST['password1']) && empty($_POST['password2']) && empty($_POST['email1']) && empty($_POST['email2']) && empty($_POST['bday'])){
    echo"Kom op, vul alles in";
    echo "<meta http-equiv='refresh' content='5;URL=register.php' />";
    exit();

}
else{
    $email1 = $_POST['email1'];
    $email2 = $_POST['email2'];
    $pass1 = $_POST['password1'];
    $pass2 = $_POST['password2'];

    if(email1 == email2){
        if(pass1 == pass2){

        }
        else{
            echo "<meta http-equiv='refresh' content='5;URL=register.php' />";
            echo"Je wachtwoorden komen niet overeen";
            exit();
        }
    }
    else{
        echo "<meta http-equiv='refresh' content='5;URL=register.php' />";
        echo "Je email gegevens komen niet overeen";
        exit();

    }

}


}
else{


$form = <<<EOT
<form method="post" action="register.php">
Gebruikersnaam:     <input type="text" name="username" placeholder="type hier je gebruikers naam"/><br /><br />
wachtwoord:         <input type="password" name="password1" placeholder="type hier je wachtwoord"/><br /><br />
wachtwoord opnieuw: <input type="password" name="password2" placeholder="type je wachtwoord opnieuw in"/><br /><br />
email:              <input type="text" name="email1" placeholder="type hier je email"/><br /><br />
email opnieuw:      <input type="text" name="email2" placeholder="type hier je email opnieuw"/><br /><br />
Geboorte datum:     <input type="date" name="bday"/ placeholder="type je geboorte datum hier"><br /><br />
<input type="submit" name="submit"/>
</form>


EOT;

echo $form;
}
?>

它只是显示

else{
        echo "<meta http-equiv='refresh' content='5;URL=register.php' />";
        echo "Je email gegevens komen niet overeen";

Answer 1

尝试更改：

    if(email1 == email2){
    if(pass1 == pass2){

为：

    if($email1 == $email2){
    if($pass1 == $pass2){

Answer 2

你有一个错字pass1 == pass2。此外，您可能想要更改：

if(empty($_POST['username']) &&...

到

if(empty($_POST['username']) OR...

PHP表单验证不起作用

2 个答案: