我正试图得到这个结果:
这就是我现在所拥有的(我现在只想把结果放在左边的元素上):
我试图让这个左箭头透明,但我找不到如何做到这一点。
CSS代码:
.main_container .photo_container .mask a {
color: #FFFFFF;
font-size: 25px;
position: relative;
}
.main_container .photo_container .mask a:first-child {
border: 1px solid #FFFFFF;
padding: 5px 11px 7px;
}
.main_container .photo_container .mask a:first-child::before {
border-bottom: 7px solid transparent;
border-right: 7px solid rgba(0, 0, 0, 0.2);
border-top: 7px solid transparent;
content: "";
display: inline-block;
left: -8px;
position: absolute;
top: 20px;
}
.main_container .photo_container .mask a:first-child::after {
border-bottom: 24px solid transparent;
border-right: 25px solid #eee;
border-top: 24px solid transparent;
content: "";
display: inline-block;
left: -26px;
position: absolute;
top: -1px;
}
HTML代码:
<div class="photo_container">
<img src="images/placeholder/car1.png" class="img-responsive" alt="" />
<div class="mask">
<a href=""><i class="fa fa-search"></i></a>
<a href=""><i class="fa fa-link"></i></a>
</div>
</div>
你能帮助我吗?
答案 0 :(得分:4)
如果您不介意使用transform
,这很简单:
在现有元素之后制作一个伪元素,将其置于正确的一侧,并将其旋转45度。
使用s = q / sqrt(2)
得到70.71%的数字,其中s
是正方形的一侧,q
是对角线。
.arrow
{
border: 1px white;
border-style: solid solid solid none;
position: relative;
width: 50px;
height: 50px;
}
.arrow::after
{
content: "";
display: block;
top: 50%;
left: 0;
position: absolute;
border: 1px white;
border-style: none none solid solid;
width: 70.71%; /* the side of a square is 70.71% the length of it's diagonal */
height: 70.71%;
transform: translate(-50%, -50%) rotate(45deg);
}
最后,我们可以更改显示的边框,以及使箭头显示在所需边上的绝对位置:
body
{
background-color: black;
padding: 50px;
}
.arrow_left,
.arrow_right
{
display: inline-block; /* just to get them next to eachother */
border: 1px white;
position: relative;
width: 50px;
height: 50px;
}
.arrow_left { border-style: solid solid solid none; }
.arrow_right { border-style: solid none solid solid; }
.arrow_left::after,
.arrow_right::after
{
content: "";
display: block;
top: 50%;
position: absolute;
border: 1px white;
width: 70.71%; /* the side of a square is 70.71% the length of it's diagonal */
height: 70.71%;
transform: translate(-50%, -50%) rotate(45deg);
}
.arrow_left::after
{
left: 0;
border-style: none none solid solid;
}
.arrow_right::after
{
left: 100%;
border-style: solid solid none none;
}
&#13;
<div class="arrow_left"></div>
<div class="arrow_right"></div>
&#13;
答案 1 :(得分:0)
答案 2 :(得分:0)
您尝试使用border来实现透明三角形。它不起作用。因此,让我们考虑实现我们想要的其他方式。 我创建了简单的演示 - 任何三角形由2行(需要简单的三角知识)。 http://codepen.io/anon/pen/PPbxEQ - 我在css中使用了一些变量,所以在这种情况下我使用了手写笔 - 更喜欢阅读源代码,而不仅仅是编译结果。 我们为第一个图标创建一个伪元素。旋转它并评估新的高度。比改变变换起源。简单。
我们改变角度 - 并重新计算cos(角度);
*,
*:before,
*:after {
box-sizing: inherit;
}
html {
box-sizing: border-box;
}
body {
display: flex;
justify-content: center;
align-items: center;
background-image: url("http://7-themes.com/data_images/out/2/6775415-beautiful-images.jpg");
background-size: cover;
background-repeat: no-repeat;
background-position: 0 0;
overflow: hidden;
}
html,
body {
width: 100%;
height: 100%;
padding: 0;
margin: 0;
}
.Icons {
width: 50vmin;
height: 25vmin;
display: flex;
}
.Icon {
flex: 1;
border-color: currentColor;
border-style: solid;
display: flex;
align-items: center;
justify-content: center;
font-size: calc(2vw + 2vh + 4vmin);
color: #fff;
position: relative;
}
.Icon + .Icon {
margin-left: -1px;
}
.Icon:first-of-type {
border-width: 1px 1px 1px 0;
}
.Icon:last-of-type {
border-width: 1px 0 1px 1px;
}
.Icon:first-of-type:before,
.Icon:first-of-type:after,
.Icon:last-of-type:before,
.Icon:last-of-type:after {
content: '';
position: absolute;
margin: auto;
color: inherit;
background-color: currentColor;
width: 1px;
height: calc(50% / 0.866025404); /* Our angle is 30deg, so formula is calc(50% / cos(angle)) */
}
.Icon:first-of-type:before,
.Icon:first-of-type:after {
left: 0;
}
.Icon:first-of-type:before {
top: 0;
transform: rotateZ(30deg);
transform-origin: top;
}
.Icon:first-of-type:after {
bottom: 0;
transform: rotateZ(-30deg);
transform-origin: bottom;
}
.Icon:last-of-type:before,
.Icon:last-of-type:after {
right: 0;
}
.Icon:last-of-type:before {
top: 0;
transform: rotateZ(-30deg);
transform-origin: top;
}
.Icon:last-of-type:after {
bottom: 0;
transform: rotateZ(30deg);
transform-origin: bottom;
}
<div class="Icons">
<div class="Icon">I</div>
<div class="Icon">O</div>
</div>