我有一个输出的查询: -
indicator1,company1,value1
indicator1,company2,value2
indicator1,company3,value3
indicator2,company1,value4
indicator2,company2,value5
indicator2,company3,value6
....
如何将此输出转换为以下json结构: -
{
indicator1 :{
"companies" : ["company1","company2","company3"],
"values" : ["value1","value2","value3"]
},
indicator2 :{
"companies" : ["company1","company2","company3"],
"values" : ["value4","value5","value6"]
}
}...
我正在使用postgres 9.4
答案 0 :(得分:1)
使用to_json()
, json_build_object()
和json_agg()
:
with q1 as (
select * from
(values
('indicator1', 'company1', 'value1'),
('indicator1', 'company2', 'value2'),
('indicator1', 'company3', 'value3'),
('indicator2', 'company1', 'value4'),
('indicator2', 'company2', 'value5'),
('indicator2', 'company3', 'value6')
) alias(ind, comp, val)
),
q2 as (
select ind, to_json(array_agg(comp)) companies, to_json(array_agg(val)) "values"
from q1
group by 1
order by 1
),
q3 as (
select companies, "values"
from q2
),
q4 as (
select json_build_object(ind, row_to_json (q3)) obj
from q2
join q3 on q2.companies::text = q3.companies::text and q2."values"::text = q3."values"::text
)
select json_agg(obj)
from q4;
替代压缩解决方案,可避免笨拙的连接条件:
with q1 as (
select * from
(values
('indicator1', 'company1', 'value1'),
('indicator1', 'company2', 'value2'),
('indicator1', 'company3', 'value3'),
('indicator2', 'company1', 'value4'),
('indicator2', 'company2', 'value5'),
('indicator2', 'company3', 'value6')
) alias(ind, comp, val)
),
q2 as (
select ind, to_json(array_agg(comp)) companies, to_json(array_agg(val)) "values"
from q1
group by 1
order by 1
)
select json_agg(
json_build_object(
ind,
json_build_object(
'companies', companies,
'values', "values")
)
)
from q2