Question

对于我的远程推送通知，我在AppDelegate

中处理了这样的问题

-(void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo
{
    dm=[DataManager sharedManager];

    self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];

    dm.screenHight=[UIScreen mainScreen].bounds.size.height;
    dm.screenWidth=[UIScreen mainScreen].bounds.size.width;
    NSLog(@"^^^^^^^^^^^^^^ Screen hight ^^^^^^^^^^^^^ %i",dm.screenHight);

    // for PAYPAL

    [PayPalMobile initializeWithClientIdsForEnvironments:@{PayPalEnvironmentProduction : @"YOUR_CLIENT_ID_FOR_PRODUCTION",PayPalEnvironmentSandbox : @"AQhrXRAyHg6nuJCma6vkl1ZtxmWUynzuf2temitMSJEZf8n74p9iKAt6TgSf"}];

    /// FOR PAYPAL
    NSLog(@"%@",userInfo);
    NSDictionary *dictionary=[userInfo objectForKey:@"jsonContent"];
    dm.notificationDictionary=dictionary;
    if ( application.applicationState == UIApplicationStateActive )
    {
         UIViewController *viewController1;
         viewController1 = [[SplashViewController alloc] initWithNibName:@"SplashViewController" bundle:nil];

         UINavigationController *aNavigationController=[[UINavigationController alloc] initWithRootViewController:viewController1];

         self.navigationcontroller = aNavigationController ;
         self.navigationcontroller.navigationBar.hidden=YES;

         [self.window setRootViewController:self.navigationcontroller];
         [self.window makeKeyAndVisible];  
    }
    else
    {
        UIViewController *viewController1;
        viewController1 = [[SplashViewController alloc] initWithNibName:@"SplashViewController" bundle:nil];

        UINavigationController *aNavigationController=[[UINavigationController alloc] initWithRootViewController:viewController1];

        self.navigationcontroller = aNavigationController ;
        self.navigationcontroller.navigationBar.hidden=YES;

        //[self.window addSubview:[self.navigationcontroller view]];
        //[self.window setRootViewController:viewController1];
        [self.window setRootViewController:self.navigationcontroller];
        [self.window makeKeyAndVisible];
    }
}

这很好用。但我的问题是，当应用程序处于活动状态时，它会在单击通知之前自动重定向到相关页面。但我希望将应用程序当前屏幕保持在forground状态，并且只有用户将通知重定向到相关性页面。我怎样才能做到这一点？请帮我。感谢

Answer 1

如果您的应用处于有效状态，您可以在UIAlertView中显示通知详细信息。用户将通过警报执行操作。但你不能指望这种状态下的通知。

UIApplicationState appState = [application applicationState];
    if (appState == UIApplicationStateActive) {
        NSString *cancelTitle = @"Close";
        NSString *showTitle = @"Show";
        NSString *message = [[userInfo valueForKey:@"aps"] valueForKey:@"alert"];
        UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@“Your Title”
                                                            message:message
                                                           delegate:self
                                                  cancelButtonTitle:cancelTitle 
                                                  otherButtonTitles:showTitle, nil];
        [alertView show];
        return;
    }

如何在AppDelegate中的didreceiveRemoteNotification中处理远程推送通知

1 个答案: