Question

我正在尝试使用多个benefit_id附加summary_attribute（value = 2004687）查找所有coverage_set_id。没有GROUP BY＆amp ;;查询似乎工作正常。有部分，但一旦我添加这些行（对于COUNT）我的结果是不正确的。只是试图获得重复的coverage_set_id。

通过OBDC数据库传递查询：

SELECT DISTINCT
    b.coverage_set_id,
    COUNT (b.coverage_set_id) AS "COUNT"

FROM
    coverage_set_detail_view a
    JOIN contracts_by_sub_group_view b ON b.coverage_set_id = a.coverage_set_id
    JOIN request c ON c.request_id = b.request_id

WHERE
    b.valid_from_date BETWEEN to_date('10/01/2010','mm/dd/yyyy')
    AND to_date('12/01/2010','mm/dd/yyyy')
    AND c.request_status = 1463
    AND summary_attribute = 2004687
    AND benefit_id <> 1092333

GROUP BY
    b.coverage_set_id

HAVING
    COUNT (b.coverage_set_id) > 1

我的结果如下：

-----------------------
COVERAGE_SET_ID | COUNT
-----------------------
4193706         | 8
4197052         | 8
4193926         | 112
4197078         | 96
4174168         | 8

我期待所有COUNT都是2.谢谢。

:: EDIT ::

解决方案：

SELECT
c.coverage_set_id AS "COVERAGE SET ID",
c1.description AS "Summary Attribute",
count(d.benefit_id) AS "COUNT"

FROM (
SELECT DISTINCT coverage_set_id

FROM contracts_by_sub_group_view

WHERE
    valid_from_date BETWEEN '01-OCT-2010' AND '01-DEC-2010'
    AND request_id IN (
        SELECT request_id
        FROM  request
        WHERE request_status = 1463)
) a

JOIN coverage_set_master e ON e.coverage_set_id = a.coverage_set_id
JOIN coverage_set_detail c ON c.coverage_set_id = a.coverage_set_id
JOIN benefit_summary d ON d.benefit_id = c.benefit_id
 AND d.coverage_type = e.coverage_type
JOIN codes c1 ON c1.code_id = d.summary_attribute

WHERE
d.summary_attribute IN (2004687, 2004688)
AND summary_structure = 1000217

GROUP BY c.coverage_set_id, c1.description

HAVING COUNT(d.benefit_id) > 1

ORDER BY c.coverage_set_id, c1.description

这些是结果：

COVERAGE SET ID  |  SUMMARY ATTRIBUTE  |  COUNT
-------------------------------------------------
4174168          |  INPATIENT          |   2
4174172          |  INPATIENT          |   2
4191828          |  INPATIENT          |   2
4191832          |  INPATIENT          |   2
4191833          |  INPATIENT          |   2
4191834          |  INPATIENT          |   2
4191838          |  INPATIENT          |   2
4191842          |  INPATIENT          |   2
4191843          |  INPATIENT          |   2
4191843          |  OUTPATIENT         |   2
4191844          |  INPATIENT          |   2
4191844          |  OUTPATIENT         |   2

Answer 1

SELECT的HAVING和count部分中的coverage_set_id应该是benefit_id。

由于benefit_id也在表a中，您可以执行以下操作

SELECT  
    a.coverage_set_id,  
    COUNT (a.benefit_id) AS "COUNT"  

FROM  
    coverage_set_detail_view a  

WHERE  
    a.coverage_set_id in (
        SELECT b.coverage_set_id 
        FROM contracts_by_sub_group_view b
        WHERE b.valid_from_date BETWEEN to_date('10/01/2010','mm/dd/yyyy') AND to_date('12/01/2010','mm/dd/yyyy'))
    AND a.coverage_set_id in (
        SELECT b2.coverage_set_id
        FROM contracts_by_sub_group_view b2
        INNER JOIN request c on c.request_id=b2.request_id
        WHERE c.request_status = 1463)
    AND ?.summary_attribute = 2004687  
    AND a.benefit_id <> 1092333  

GROUP BY  
    a.coverage_set_id  

HAVING  
    COUNT (a.benefit_id) > 1

这将删除在FROM上发生的JOIN放大，因为不需要这些表来提取coverage_set_id和benefit_id。其他2个表的唯一剩余需求是根据WHERE子句中的条件过滤掉数据。

我不确定表summary_attribute是什么，但它会遵循与valid_from_date，request_status或benefit_id类似的模式。

MS Access Pass Through Query使用多个表查找重复项

:: EDIT ::

1 个答案: