我正在开发skype插件。它应该在通话期间播放音频文件。
音频播放器使用naudio库
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<ul>
<li>Link 1</li>
<li>Link 2</li>
<li>Link 3</li>
<li>Link 4</li>
<li>Link 5</li>
<li>Link 6</li>
<li>Link 7</li>
<li>Link 8</li>
<li>Link 9</li>
<li>Link 10</li>
</ul>
在skype插件类中,我创建了NetworkStream和TcpListener。使用来自播放器的事件来获取缓冲区数据并写入网络流 WriteToStream(buffer,0,num); 在通话开始时我改变了Skype的输入
public class AudioPlayback : IDisposable, IPlayer
{
WaveStream _outStream;
IWavePlayer _player;
IWaveIn _recorder;
public event Action<byte[], int> DataAvailable;
public AudioPlayback()
{
_recorder = new WaveInEvent();
_recorder.WaveFormat = new WaveFormat(16000, 16, 1);
_recorder.DataAvailable += OnRecorderDataAvailable;
}
private void OnRecorderDataAvailable(object sender, WaveInEventArgs e)
{
if (DataAvailable!= null)
{
DataAvailable(e.Buffer, e.BytesRecorded);
}
}
public void LoadFile(string fileName)
{
_outStream = new Mp3FileReader(fileName);
if (_outStream.WaveFormat.Encoding != WaveFormatEncoding.Pcm)
{
_outStream = WaveFormatConversionStream.CreatePcmStream(_outStream);
}
}
private void CreatePlayer()
{
if (_player == null)
{
var waveOut = new WaveOut();
waveOut.DesiredLatency = 200;
waveOut.NumberOfBuffers = 2;
waveOut.DeviceNumber = 0;
_player = waveOut;
}
}
public void Play()
{
CreatePlayer();
if (_player.PlaybackState != PlaybackState.Playing)
{
if (_player.PlaybackState == PlaybackState.Stopped)
_recorder.StartRecording();
_player.Init(_outStream);
_player.Play();
}
}
}
与此斗争了好几个小时。最后只有在打开立体声混音器(录音设备)时才能在另一个Skype上获得声音。 问题:这是正确的方法吗?我不喜欢播放声音并捕获它。但在这里我有一个积极的事情 - 我使用适合skype的参数完全捕获。