Question

您好我正在尝试在文件路径进入字典之前对其进行子串。我试图声明起点但是给出了一个错误：

StartIndex不能大于字符串的长度。参数名称：startIndex

这是我的代码

$(msg)

任何帮助都会很棒。

我也尝试过做

private  Dictionary<string,int> CreateDictionary(log logInstance)
        {
            Dictionary<string, int> dictionary = new Dictionary<string, int>();
            for (int entryIdex = 0; entryIdex < logInstance.logentry.Count(); entryIdex++)
            {
                logLogentry entry = logInstance.logentry[entryIdex];
                for (int pathIdex = 0; pathIdex < entry.paths.Count(); pathIdex++)
                {
                    logLogentryPath path = entry.paths[pathIdex];
                    string filePath = path.Value;
                    filePath.Substring(63);
                    string cutPath = filePath;
                    if (dictionary.ContainsKey(cutPath))
                    {
                        dictionary[cutPath]++;
                    }
                    else
                    {
                        dictionary.Add(cutPath, 1);
                    }
                }
            }
            return dictionary;
        }

和

filePath.Substring(0, 63);

Answer 1

C＃中的字符串是不可变的（一旦创建了一个字符串就无法修改），这意味着当您设置string cutpath = filepath时，您将cutpath的值设置为path.Value没有将filepath.SubString(63)的值分配给任何东西。修复此更改

string filePath = path.Value;
filePath.Substring(63); // here is the problem
string cutPath = filePath;

要

string filePath = path.Value;
string cutPath = filePath.Substring(63);

Answer 2

首先：

// It's do nothing
filePath.Substring(63);

// Change to this
filePath = filePath.Substring(63);

第二

63是我从每个文件路径子串的字符条目如下所示：/ GEM4 / trunk / src / Tools / TaxMarkerUpdateTool / Tax Marker Ripper v1，最后一位是我想要的真实信息显示的是：/DataModifier.cs

使用63是一个坏主意。最好找到最后一个“/”并将其位置保存到某个变量。

Answer 3

感谢大家的帮助

我的代码现在有效，看起来像这样：

Private  Dictionary<string,int> CreateDictionary(log logInstance)
    {
        Dictionary<string, int> dictionary = new Dictionary<string, int>();
        for (int entryIdex = 0; entryIdex < logInstance.logentry.Count(); entryIdex++)
        {
            logLogentry entry = logInstance.logentry[entryIdex];
            for (int pathIdex = 0; pathIdex < entry.paths.Count(); pathIdex++)
            {
                logLogentryPath path = entry.paths[pathIdex];
                string filePath = path.Value;

                if (filePath.Length > 63)
                {
                    string cutPath = filePath.Substring(63);
                    if (dictionary.ContainsKey(cutPath))
                    {
                        dictionary[cutPath]++;
                    }
                    else
                    {
                        dictionary.Add(cutPath, 1);
                    }
                }
            }
        }
        return dictionary;
    }

Answer 4

阅读您的评论，您似乎只需要文件路径中的文件名。有一个内置的实用程序可以在任何路径上实现这一点。

来自MSDN：

<强> Path.GetFileName

返回指定路径字符串的文件名和扩展名。

https://msdn.microsoft.com/en-us/library/system.io.path.getfilename%28v=vs.110%29.aspx

这是一个让您入门的代码示例。

string path = @"/GEM4/trunk/src/Tools/TaxMarkerUpdateTool/Tax Marker Ripper v1/Help_Document.docx";

string filename = System.IO.Path.GetFilename(path);

Console.WriteLine(filename);

<强>输出

Help_Document.docx

以下是修改后的代码;

Private  Dictionary<string,int> CreateDictionary(log logInstance)
    {
        Dictionary<string, int> dictionary = new Dictionary<string, int>();
        for (int entryIdex = 0; entryIdex < logInstance.logentry.Count(); entryIdex++)
        {
            logLogentry entry = logInstance.logentry[entryIdex];
            for (int pathIdex = 0; pathIdex < entry.paths.Count(); pathIdex++)
            {
                logLogentryPath path = entry.paths[pathIdex];
                string filePath = path.Value;

                // extract the file name from the path
                string cutPath = System.IO.Path.GetFilename(filePath);

                if (dictionary.ContainsKey(cutPath))
                {
                    dictionary[cutPath]++;
                }
                else
                {
                    dictionary.Add(cutPath, 1);
                }
            }
        }
        return dictionary;
    }

子串文件路径

4 个答案: