Question

我的问题很简单，但我对解决方案视而不见。我想做的就是打开单击相应的菜单按钮或子部分时的简单对话框。并且在使用新的，更新的语法进行连接时这样做。这是一个小而短的简单代码。

from PySide.QtCore import *
from PySide.QtGui import *
import sys

import TheMainWindow
import PutnickiVozDialog


class TheApp(QMainWindow, TheMainWindow.Ui_MainWindow):
    def __init__(self, parent=None):
        super(TheApp,self).__init__(parent)
        self.setupUi(self)

        self.actionDodaj_Novi.connect(self.openNewPutnicki)


    def openNewPutnicki(self):
        self.putDialog = QDialog(self)
        self.putUi = PutnickiVozDialog.Ui_putnickiSearchDialog()
        self.putUi.setupUi(self.putDialog)
        self.putDialog.show()


theApp = QApplication(sys.argv)
theWindow = TheApp()
theWindow.show()
theApp.exec_()

我按照教程完成了这些操作。但我得到以下错误报告。我不知道我错过了什么。

C:\Python34\python.exe "C:/Projects/Xml Database Project/PyCharm Workspace/TheApplication.py"
Traceback (most recent call last):
  File "C:/Projects/Xml Database Project/PyCharm Workspace/TheApplication.py", line 45, in <module>
    theWindow = TheApp()
  File "C:/Projects/Xml Database Project/PyCharm Workspace/TheApplication.py", line 16, in __init__
    self.actionDodaj_Novi.connect(self.openNewPutnicki)
TypeError: PySide.QtCore.QObject.connect(): not enough arguments

Process finished with exit code 1

如果我对这里的事情视而不见，我很抱歉。但它只是赢了工作。提前谢谢！

在Pyside打开一个简单的对话框

0 个答案: