Question

有以下代码：

  $scope.clickByPoint = function(marker, eventName, point) {
    var geocoder, location;
    $scope.options.info.point = point;
    $scope.options.info.show = true;
    $scope.searched = false;
    $scope.address = "";
    geocoder = new google.maps.Geocoder();
    location = {
      lat: parseFloat(point.latitude),
      lng: parseFloat(point.longitude)
    };
    geocoder.geocode({ location: location }, function(results, status) {
      $scope.searched = true;
      if (status === google.maps.GeocoderStatus.OK) {
        $scope.address = results[0].formatted_address;
      }
      return $scope.$digest();
    });
  };

请告诉我，我怎么可以'间谍'打电话给'geocoder.geocode'并执行假代码而不是它？提前致谢！

Answer 1

如果我理解正确，你想要调用地理编码功能的模拟，只是为了检查你的控制器功能是否正确对待它，是吗？

您应该使用Jasmine Spy＆＃34;＆＃34;调用并返回值＆＃34;，这样您就可以调用测试中的函数并硬编码您希望此函数返回的结果。例如：

describe("A spy, when configured to fake a return value", function() {
  var foo, bar, fetchedBar;

  beforeEach(function() {
    foo = {
      setBar: function(value) {
        bar = value;
      },
      getBar: function() {
        return bar;
      }
    };

    spyOn(foo, "getBar").and.returnValue(745);

    foo.setBar(123);
    fetchedBar = foo.getBar();
  });

  it("tracks that the spy was called", function() {
    expect(foo.getBar).toHaveBeenCalled();
  });

  it("when called returns the requested value", function() {
      expect(fetchedBar).toEqual(745);
  });
});

您可以在此处查看茉莉花文档以获取更多信息：http://jasmine.github.io/2.0/introduction.html#section-Spies:_and.returnValue

茉莉花间谍功能调用

1 个答案: