Question

我有两个场景。第一个有一个UIWebView。让我们说用户点击这个链接：

<a href="startSecondScene">start second scene</a>

第二个应该没有在第一个中加载链接。

ViewController.m代码：

#import "ViewController.h"

@interface ViewController ()

@end

@implementation ViewController

 - (void)viewDidLoad {
    [super viewDidLoad];
    // Do any additional setup after loading the view, typically from a nib.
    NSString *urlString = @"http://www.autoblog.com/";
    NSURL *url = [NSURL URLWithString:urlString];
    NSURLRequest *urlRequest = [NSURLRequest requestWithURL:url];
    [_udazzWebView loadRequest:urlRequest];
}

- (void)didReceiveMemoryWarning {
    [super didReceiveMemoryWarning];
    // Dispose of any resources that can be recreated.
}

@end

Answer 1

您可以使用UIWebViewDelegate中的方法：

- (BOOL)webView:(UIWebView *)webView
shouldStartLoadWithRequest:(NSURLRequest *)request
 navigationType:(UIWebViewNavigationType)navigationType
{
    if ([request.URL.absoluteString isEqualToString:@"startSecondScene"]) {
        //go to the second scene
        return NO;
    }
    return YES;
}

不要忘记_udazzWebView.delegate = self;方法中的-viewDidLoad。

你可以像这样推送新场景：

SecondViewController* _vc = [SecondViewController new];
[self.navigationController pushViewController:_vc animated:YES];

有关navigationController的更多信息，请参阅文档： https://developer.apple.com/library/ios/documentation/UIKit/Reference/UINavigationController_Class/index.html#//apple_ref/doc/c_ref/UINavigationController

希望它会有所帮助。

当用户点击另一个场景中的UIWebView中的链接时，启动一个场景

1 个答案: