Question

I need to transform using XSLT an XML input:

<CONTAINER>container1</CONTAINER>
<STOP>stop1</STOP>
<PO>po1</PO>
<PO>po2</PO>
<PO>po3</PO>
<CONTAINER>container2</CONTAINER>
<STOP>stop2</STOP>
<PO>po4</PO>
<PO>po5</PO>
<PO>po6</PO>
<STOP>stop3</STOP>
<PO>po7</PO>
<PO>po8</PO>

into

<CONTAINER>container1</CONTAINER>
<STOP>
<new_tag>Collapsed STOP</new_tag>
<PO>po1</PO>
<PO>po2</PO>
<PO>po3</PO>
</STOP>
<CONTAINER>container2</CONTAINER>
<STOP>
<new_tag>Collapsed STOP</new_tag>
<PO>po4</PO>
<PO>po5</PO>
<PO>po6</PO>
<STOP>stop3</STOP>
<PO>po7</PO>
<PO>po8</PO>
</STOP>

So basically I need to collapse all POs tag in a single STOP instead of having many STOPs, each one having a group of POs ad children.

Can someone help me on this? I'm very new to XSLT so I cannot fing a way to perform (if possible) this transformation.

Answer 1

假设

您的输入应该是格式良好的文档。我把它包裹在一个元素中就可以了。
您正在使用XSLT 2.您没有说明版本。
文档中的每个CONTAINER始终都会立即停止。
根元素的第一个子元素是CONTAINER。

这个XSLT 2转换......

<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  version="2.0">

<xsl:output indent="yes" encoding="utf-8" omit-xml-declaration="yes" />
<xsl:strip-space elements="*" />

<xsl:template match="@*|node()">
  <xsl:copy>
    <xsl:apply-templates />
  </xsl:copy>
</xsl:template>

<xsl:template match="t">
  <xsl:copy>
    <xsl:for-each-group select="*" group-starting-with="CONTAINER">
      <CONTAINER><xsl:value-of select="current-group()[self::CONTAINER]/text()" /></CONTAINER>
      <STOP>
        <new_tag>Collapsed STOP</new_tag>
        <xsl:apply-templates select="current-group()
          [not(self::CONTAINER)]      (: Excluded because we have already dealt with CONTAINER.  :)
          [position() ge 2     ]      (: Exclude the first STOP, because already dealt with.     :)
          " />
      </STOP>
    </xsl:for-each-group>
  </xsl:copy>
</xsl:template>

</xsl:stylesheet>

...将转换此输入文档......

<t>
    <CONTAINER>container1</CONTAINER>
    <STOP>stop1</STOP>
    <PO>po1</PO>
    <PO>po2</PO>
    <PO>po3</PO>
    <CONTAINER>container2</CONTAINER>
    <STOP>stop2</STOP>
    <PO>po4</PO>
    <PO>po5</PO>
    <PO>po6</PO>
    <STOP>stop3</STOP>
    <PO>po7</PO>
    <PO>po8</PO>
</t>

...进入此输出...

<t>
   <CONTAINER>container1</CONTAINER>
   <STOP>
      <new_tag>Collapsed STOP</new_tag>
      <PO>po1</PO>
      <PO>po2</PO>
      <PO>po3</PO>
   </STOP>
   <CONTAINER>container2</CONTAINER>
   <STOP>
      <new_tag>Collapsed STOP</new_tag>
      <PO>po4</PO>
      <PO>po5</PO>
      <PO>po6</PO>
      <STOP>stop3</STOP>
      <PO>po7</PO>
      <PO>po8</PO>
   </STOP>
</t>

学习笔记

请参阅my answer here，了解有关xsl：for-each-group指令的更多信息。

Answer 2

XSLT 1.0解决方案：

var videoLinks = [
    ....
];

var lastNumber = 0;
var randomNumber = function () {
    var getRandomNumber = Math.floor(Math.random() * 5);  
    if(getRandomNumber != lastNumber){
        var random = videoLinks[getRandomNumber];
        document.getElementById("videoWrapper").innerHTML = random[0];
        lastNumber = getRandomNumber;
    }else{
        randomNumber();
    }
};

randomNumber(); // To call the function on load

关键部分在这里：

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
    <xsl:output method="xml" omit-xml-declaration="yes" encoding="UTF-8" indent="yes" />

    <xsl:template match="/root">
        <root>
            <xsl:apply-templates />
        </root>

    </xsl:template>

    <xsl:template match="/root/CONTAINER">
        <xsl:copy-of select="."/>
        <xsl:apply-templates />
    </xsl:template>

    <xsl:template match="/root/STOP">
        <STOP>
            <new_tag><xsl:value-of select="." /></new_tag>
            <xsl:variable name="stopnum">
                <xsl:number level="single" count="STOP" />
            </xsl:variable>
            <xsl:for-each select="following-sibling::PO[count(preceding-sibling::STOP) = $stopnum]">
                <xsl:copy-of select="." />                
            </xsl:for-each>
        </STOP>
    </xsl:template>

    <xsl:template match="text()" />

</xsl:transform>

我们设置一个变量，告诉我们已经处理的最后一个STOP节点的位置，然后选择我们的<xsl:variable name="stopnum"> <xsl:number level="single" count="STOP" /> </xsl:variable> <xsl:for-each select="following-sibling::PO[count(preceding-sibling::STOP) = $stopnum]">中具有那么多for-each个STOP节点的所有PO节点。 / p>

请注意，我已将XML封装在preceding-sibling和<root>节点中，以使其成为有效的XML。

输入：

</root>

输出：

<root>
<CONTAINER>container1</CONTAINER>
<STOP>stop1</STOP>
<PO>po1</PO>
<PO>po2</PO>
<PO>po3</PO>
<CONTAINER>container2</CONTAINER>
<STOP>stop2</STOP>
<PO>po4</PO>
<PO>po5</PO>
<PO>po6</PO>
<STOP>stop3</STOP>
<PO>po7</PO>
<PO>po8</PO>
</root>

Insert a parent node for a group of nodes in XSLT

2 个答案:

假设

学习笔记