Question

我收到Jira API的回复，需要反序列化为数据模型：

com.atlassian.greenhopper.service.sprint.Sprint@40675167[id=10151,rapidViewId=171,state=CLOSED,name=Sprint 37.1,startDate=2015-07-30T16:00:22.000+03:00,endDate=2015-08-13T16:00:00.000+03:00,completeDate=2015-08-13T14:31:34.343+03:00,sequence=10151]

这实际上是当前sprint的问题。我需要将它反序列化为类似的模型：

public class Model
{
    public string name { get; set; }
    ...
}

我已经使用com.atlassian.greenhopper.service.sprint.Sprint@40675167删除了所有不需要的信息，例如Regex pattern \[(.*?)\]，所以我有括号和所有内部信息。

现在我完全停止尝试找到将此字符串转换为数据模型的方法。

Answer 1

在Atlassian Answers页面找到以下thread，似乎没有该内部Object的JSON表示。如该线程中的示例所示：

customfield_10007:[
"com.atlassian.greenhopper.service.sprint.Sprint@a29f07[rapidViewId=<null>,state=CLOSED,name=NORD - Sprint 42,startDate=2013-07-29T06:47:00.000+02:00,endDate=2013-08-11T20:47:00.000+02:00,completeDate=2013-08-14T15:31:33.157+02:00,id=107]",
"com.atlassian.greenhopper.service.sprint.Sprint@769133[rapidViewId=<null>,state=ACTIVE,name=NORD - Sprint 43,startDate=2013-08-14T15:32:47.322+02:00,endDate=2013-08-23T15:32:47.322+02:00,completeDate=<null>,id=117]"
],

响应确实是一个JSON数组，但数组本身包含CSV，因此您可以使用以下内容来解析：

   public class DataObject
    {
        public string id { get; set; }
        public string rapidViewId { get; set; }
        public string state { get; set; } 
        public string name { get; set; }
        public string startDate { get; set; }
        public string endDate { get; set; }
        public string completeDate { get; set; }
        public string sequence { get; set; }
    }


    public class Program
    {
        private const string sampleStringData =
            @"[id=10151,rapidViewId=171,state=CLOSED,name=Sprint 37.1,startDate=2015-07-30T16:00:22.000+03:00,endDate=2015-08-13T16:00:00.000+03:00,completeDate=2015-08-13T14:31:34.343+03:00,sequence=10151]";


        static void Main(string[] args)
        {
            var dataObject = new DataObject();

            string[][] splitted;
            var sampleWithNoBrackets = sampleStringData.Substring(1,sampleStringData.Length-2);
            splitted = sampleWithNoBrackets.Split(',').Select(p => p.Split('=')).ToArray();

            dataObject.id           = splitted[0][1];
            dataObject.rapidViewId  = splitted[1][1];
            dataObject.state        = splitted[2][1];
            dataObject.name         = splitted[3][1];
            dataObject.startDate    = splitted[4][1];
            dataObject.endDate      = splitted[5][1];
            dataObject.completeDate = splitted[6][1];
            dataObject.sequence     = splitted[7][1];

            Console.ReadKey();
        }
    }

以下是上述输出：

将CSV字符串反序列化为C＃对象

1 个答案: