我的程序运行没有问题,没有编译错误。
我的if语句的目的是选择是否向左/右移动字母,我试图用if语句导致2个函数,但无论来自cin >> z;
的输入,它总是使用CipherR 。任何人都可以帮我解决这个问题吗?
//Start of Document
#include <WinUser.h> //Gives access to windows form library
#include "StdAfx.h" //Standard prefix for vb to save
#include <iostream> //Enables I/O stream cin/cout
#include <string> //Ensures that string data can be assigned
#include <Windows.h> //Gives access to windows library Included libraries, above <winuser.h>
using namespace std;
//Variables
char cipherR(char);
char cipherL(char);
int y;
const string LEFT = "1";
const string RIGHT = "0";
//Main Code
int main()
{
string input; //Declares string variable for temp storage
//MessageBox
int WinUserMessageBox(HWND hWnd, LPCTSTR lpText, LPCTSTR lpCaption, UINT uType); //defines MessageBox parameters
const int message = MessageBox(NULL, L"Is your location secure?", L"Warning", MB_YESNOCANCEL); //sets up listener for messagebox response
//Switch Response
switch (message) //Initialise case study
{
case IDYES: //Runs this if Yes is selected
//cipher code block
do {
cout << "Enter text to be ciphered/deciphered." << endl;
cout << "Enter blank line to quit." << endl;
getline(cin, input); //Prompts for User Input, stores into temporary var
string output = ""; //Checks for blank input
cout << "Shift Left(1) or Right(0)? \n";
string z; //L or R definer
std::cin >> z;
cout << "Enter number to shift\n";
cin >> y;
if (z == LEFT)
{
for (int x = 0; x < input.length(); x++) // Loops until string.length is reached.
{
output += cipherR(input[x]);
}
} //Adds the value of expression to the value of a variable and assigns the result to the variable.
else if (z == RIGHT)
{
for (int x = 0; x < input.length(); x++) // Loops until string.length is reached.
{
output += cipherL(input[x]); //Adds the value of expression to the value of a variable and assigns the result to the variable.
}
};
cout << output << endl; // If input is blank will end process
} while (!input.length() == 0); //Loops while input.length is NOT equal to 0
break;
//alternate message responses
case IDNO: //Runs this if No is selected
MessageBox(NULL, L"Agents are converging on your location now.", L"Run!", NULL);
return 0;
break;
case IDCANCEL: //Runs this if cancel is selected
MessageBox(NULL, L"Why open this is you're gonna back out?", L"Alert", NULL);
return 0;
break;
}
}
//functions
char cipherR(char c) //function caesar, called into main
{
if (isalpha(c)) //checks if is part of the alphabet
{
c = toupper(c); //ignores casing of input for universal input
c = (((c - 65) + y) % 26) + 65; //performs caesar cipher with algebraic equation
return c; //returns encrypted data
}
if (!isalpha(c)) //if is not alphabetic will make blank
{
return 0; //returns blank
}
// if c isn't alpha, just send it back
}
char cipherL(char c) //function caesar, called into main
{
cout << "This Is left";
if (isalpha(c)) //checks if is part of the alphabet
{
c = toupper(c); //ignores casing of input for universal input
c = (((c - 65) - y) % 26) + 65; //performs caesar cipher with algebraic equation
return c; //returns encrypted data
}
if (!isalpha(c)) //if is not alphabetic will make blank
{
return 0; //returns blank
}
// if c isn't alpha, just send it back
}
//end of sheet
答案 0 :(得分:0)
我相信你的功能已经发生了变化。在
if (z == LEFT)
{
for (int x = 0; x < input.length(); x++) // Loops until string.length is reached.
{
output += cipherR(input[x]);
}
} //Adds the value of expression to the value of a variable and assigns the result to the variable.
else if (z == RIGHT)
{
for (int x = 0; x < input.length(); x++) // Loops until string.length is reached.
{
output += cipherL(input[x]); //Adds the value of expression to the value of a variable and assigns the result to the variable.
}
};
当您进入“左”if语句时,当您应该呼叫cipherR()
时,您正在呼叫cipherL()
。您还需要在调用cipherL()
时修正“正确”。修正版:
if (z == LEFT)
{
for (int x = 0; x < input.length(); x++) // Loops until string.length is reached.
{
output += cipherL(input[x]);
// ^ L here
}
} //Adds the value of expression to the value of a variable and assigns the result to the variable.
else if (z == RIGHT)
{
for (int x = 0; x < input.length(); x++) // Loops until string.length is reached.
{
output += cipherR(input[x]); //Adds the value of expression to the value of a variable and assigns the result to the variable.
// ^ R here
}
};
答案 1 :(得分:0)
看起来你认为-1 % 26
是25
它不是 - 它是1或-1,具体取决于实现。
在您的实施中,它显然是正面的,因为您在两个班次都得到相同的结果。
左移不能使用模数 相反,使用重复添加:
c = c - y;
while (c < 'A')
{
c += 26;
}
您还想查看每个案例中您要调用的功能,因为您可以切换它们。