我正在尝试在表单中要求上传文件,但无法使其正常工作。有任何想法吗?我宁愿回应页面上的php错误与javascript弹出窗口。谢谢你看看:
<?php
// initialize $file1
$file1 = $_POST['file1'];
// check upload of $file1
if ($file1 == '' ) {
$error = "Please upload an image";
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Require upload of an file</title>
</head>
<body>
<?php if ($error) {echo $error;} ?>
<br /><br /><br />
<form id="form1" name="form1" method="post" action="nextpage.php">
<input type="file" size="8" name="file1" />
<input name="Submit" type="Submit" />
</form>
</body>
</html>
答案 0 :(得分:2)
请参阅this tutorial它拥有您需要的一切。
总结一下:
enctype="multipart/form-data"
标记中使用method="POST"
和<form>
。$_FILES['uploadedfile']['name']
来读取原始名称(“uploadedfile”是文件输入的名称 - 在您的示例中为“file1”)。$_FILES['uploadedfile']['tmp_name']
来读取服务器端临时文件名。$_FILES['uploadedfile']['error']
来获取可能代码的错误(如果有)see there。在您的例子中使用此表格:
<form id="form1" name="form1" method="post" action="nextpage.php" enctype="multipart/form-data">
<input type="file" size="8" name="file1" />
<input name="Submit" type="Submit" />
</form>
在“nextpage.php”中:
//Use $_FILES['file1'] to check the file upload...
print_r($_FILES['file1']);