Question

<!doctype html>
<html>
<head>
    <meta charset="utf-8" />
    <meta name="format-detection" content="telephone=no" />
    <meta name="viewport" content="user-scalable=no, initial-scale=1, maximum-scale=1, minimum-scale=1, width=device-width, height=device-height, target-densitydpi=device-dpi" />
    <link rel="stylesheet" type="text/css" href="css/index.css" />

<?php
    session_start();

    $conn = mysqli_connect("localhost", "root", "","test");

    $product_code = $_GET['product_code'];
    $sql = "SELECT * FROM test_config WHERE product_code = '$product_code'";
    $product_list = mysqli_query ( $conn, $sql);

    if($product_list = 1)
    echo"good";
    else
    echo"bad"; 
?>
</head>

<body>

<span id="tttt"></span>
<form id="msform" method="post">
<!-- progressbar -->
<ul id="progressbar">
<li class="active">

<?php While ($one_product = mysqli_fetch_assoc($product_list)) {?>


<li><?php echo $one_product['test_name']; ?></li>

<?php } ?>

<!-- <a href="index.html" >Start-Over</a>  -->
<span onclick="window.close()" style="float:right">Start-Over</span>
</ul>

<?php While ( $one_product = mysqli_fetch_assoc($product_list)  ) { 

        $num_test = $one_product['num_test'];
        $test_name = $one_product['test_name'];
        $images_pos = $one_product['images_pos'];
        $images_neg = $one_product['images_neg'];
        $images_inv = $one_product['images_inv'];
?>
<!-- fieldsets -->
<fieldset id="<?php $test_name; ?>" data-set="0">
<h2 class="fs-title"><?php echo "$test_name"; ?></h2>
<img src="images/<?php $images_pos; ?>"  class="case" data-case="1"/><br/>
<input name="<?php $test_name; ?>" type="radio" value="N" class="hide">
<img src="images/<?php $images_neg; ?>"  class="case" data-case="2"/><br/>
<input name="<?php $test_name; ?>" type="radio" value="P" class="hide">
<img src="images/<?php $images_inv; ?>"  class="case" data-case="3"/><br/>
<input name="<?php $test_name; ?>" type="radio" value="I" class="hide">
<img src="images/skip_button.fw.png"  class="case" data-case="4"/><br/>
<input name="<?php $test_name; ?>" type="radio" value="S" class="hide">
<br/>

<?php if ($num_test > 1) { ?>
<input type="button" name="next" class="next action-button" value="Next" />

<br/>
<?php if($num_test == 1) { ?>

<input type="button" name="previous" class="previous action-button" value="Previous" />
<input type="button" name="submit" id="submit" class="action-button" value="SAVE" />

</fieldset>
<?php }
$num_test --; ?>
<?php } }?>

</form>

</body>
</html>

错误：警告：mysqli_fetch_assoc（）要求参数1为mysqli_result，第41行和第52行给出的整数（包含的行）

请帮帮我谢谢!!!!! sql确实从数据库中获取数据。但是，while循环仍有一些错误。

Answer 1

通常在mysqli_query未正常运行时发生这种情况，

试试这个

 var TodoView = Backbone.View.extend({
  tagName: 'li',

  // ...
  el: $('#todo')
  // ..
});

Answer 2

我认为您的查询存在错误。你可以用这个代替你的代码吗？它应该为您提供一条错误消息，告诉您查询中的内容。如果我猜测，我会说$product_code在数据库中存储为整数，但您在查询中将其用作字符串。

$product_list = mysqli_query( $conn, $sql) or die(mysqli_error($conn));

PHP编程错误（无法运行while循环）

2 个答案: